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## #1 2012-12-22 05:15:13

jacks
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### 4 digit no.

A 4 digit no. abcd is such that 4 *(abcd) = (dcba). Then no. abcd is

## #2 2012-12-22 05:33:17

anonimnystefy
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### Re: 4 digit no.

I have that abcd=2178.

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## #3 2012-12-22 05:48:18

bobbym

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### Re: 4 digit no.

Hi;

Yes, and that is the only solution.

In mathematics, you don't understand things. You just get used to them.
Some cause happiness wherever they go; others, whenever they go.
If you can not overcome with talent...overcome with effort.

## #4 2012-12-22 06:11:18

jacks
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### Re: 4 digit no.

Yes 2178 is right answer.

How can i get it.

would you like to explain me

hanks

## #5 2012-12-22 06:20:41

bobbym

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### Re: 4 digit no.

Hi;

First thing that jumps right out at you is that the front digit is either a 1 or 2. So, the last digit is a 4 or an 8. You now only have to try 16 numbers to find all the answers.

In mathematics, you don't understand things. You just get used to them.
Some cause happiness wherever they go; others, whenever they go.
If you can not overcome with talent...overcome with effort.

## #6 2012-12-22 21:53:52

phrontister
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### Re: 4 digit no.

Hi,

a = 2...from d x 4 = even, and a x 4 must be a single-digit result (to avoid a 5-digit end product).
b = 1...from b x 4 must be a single-digit result (to keep a = 2), and 2 is already taken.
d = 8...from a x 4 = 8.
c = 7...from (c x 4) + the tens unit (3) from d x 4 must end in 1, which is only possible with c = 7 or 2; but 2 is already taken.

So, abcd is 2178.

"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

## #7 2012-12-24 02:06:37

jacks
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### Re: 4 digit no.

Thanks friends got it