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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

Hi,

I really need help seeing if I answered the following correct:

I'll give you an assumption, and ask you to provide proof for the assumption. If there is no proof for the assumption, the answer is "unfounded."

I choose A

1. If I have two coplanar lines, I must have a plane.

A-unfounded

B-Definition of a point

C-Definition of a plane

D-Given

E -Definition of a line

F -Definition of radius

*Last edited by zee-f (2012-12-12 00:41:33)*

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

hi zee-f,

I think this can be proved. Isn't a plane defined by 3 (non-colinear ) points?

How could you find 3 such points on those two lines?

But I don't understand how you can prove that with just a letter. Have you got any examples of this sort of thing?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 14,812

A is correct.

The statement isn't even true. Two lines that are actually the same line do not define a single plane, but are coplanar.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I answered A and it was incorrect .

Yeah this lesson is confusing but I did answer 14 correctly like this one :

(F ) was correct

6. In the figure above, line segment MC is equal to imaginary line segment MI.

A Given

Bunfounded

CDefinition of supplementary angles

D1267200 inches

E Definition of an octagon

F Definition of a circle: all points are equidistant from the center

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I have to use the information I know to proof the statement correct

One, who adopts patience, will never be deprived of success though it may take a long time to reach him. Imam ali (as)<3

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

stefy wrote:

Two lines that are actually the same line do not define a single plane, but are coplanar.

I did consider this, but rejected this interpretation on the grounds that 'two lines' should mean exactly two distinct lines not one line counted twice.

That's the trouble with using English to make mathematical statements. It sometimes isn't precise enough.

As zee-f has had A marked wrong, I think we have further evidence that the questioner was thinking that way too.

So let's assume the lines are either (i) distinct and parallel or (ii) they cross at a point

So we either have 4 distinct points or at least 3.

What do we need to define a plane?

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

Hi,

According to my online courses A plane is defined by any of the following:

three points not lying on a line

a line and a point not lying on the line

two lines which intersect in a single point or are parallel

So I think C would be a correct answer

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

Yes, C sounds good. But I thought you had to supply the proof as well. Maybe not.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I am still confused on what am really doing

I got 6 incorrect out of 20

I choose A and it was incorrect

7. In the figure above, line segment EJ is equal to line segment JM

A Definition of radius

Bunfounded

CDefinition of an octagon

D1267200 inches

E Given

F Definition of supplementary angles

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

6/20 eeekkk!

Oh hang on. 6 wrong. Oh that's not so bad. 70% is a good score.

But we'll get them sorted. Don't worry.

I need to see the diagram for this one.

bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

yup 14/ 20

The lesson uses the same chart for all the questions that use the chart

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

hi zee-f,

Oh, that diagram. I remember that from another set of questions.

So EJ = JM ? They're not telling that; they're asking is it true?

Take a look at the diagram. Is J half way along EM ?

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

no EJ ≠ Jm

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

So B would be a good answer ?

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

Yes, that's what I would choose.

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

I choose E and it was incorrect

my new answer is D

14. If a central angle is 30 degrees, then the arc it defines is also 30 degrees.

A Given

BDefinition of an inscribed angle

Cunfounded

DProperties of a central angle

E Properties of an arc

F Definition of radius

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

I see why you said E to start with. I would say that D and E are the same. But if E isn't acceptable, D seems good to me.

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

yeah I was stuck on which one to choose to. lol

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

E was incorrect I still don't see why O_o

16. If a radius bisects a chord, then the lengths of the parts of the radius on either side of the chord are equal.

A Given

BDefinition of a chord

Cunfounded

DDefinition of supplementary angles

E Definition of a bisector

F Definition of radius

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**bob bundy****Moderator**- Registered: 2010-06-20
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I think my diagrams will show you what to do here.

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

No the radius isn't cut into equal parts so that whole statement is incorrect So C would be a good answer

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

Yes. That's what I think.

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

2 more left

I answered C for both it was incorrect

19. The given points (4, -8), (4, -5), and (-2, -6) make a right triangle.

A Distance Formula

B Definition of a right triangle

CDefinition of a triangle

Dunfounded

E Pythagorean Theorem

F Definition of radius

20. The given points (2, -3), (-7, -7), (2, -7), and (-7, -2) make a square.

A Definition of coordinate

BPythagorean Theorem

CDefinition of a square

DDefinition of supplementary angles

E Distance Formula

F unfounded

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,092

hi

Did you try plotting the points? Have a look at my diagram.

I think you'll see what to do then.

Bob

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**zee-f****Member**- Registered: 2011-05-12
- Posts: 1,220

No I didn't plot them probably why I got the question wrong the don't make a square or a right triangle So both (unfounded)

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