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**krisper****Member**- Registered: 2005-12-20
- Posts: 19

Here is what we do:

1. We have the numbers from 1 to 10 a∈{1,2,3,4,5,6,7,8,9,10}.

2. x is the power of these numbers.

3. Take any random **integer** number x that is between 0 and +∞.

4. Calculate

1^x = b1

2^x = b2

3^x = b3

4^x = b4

5^x = b5

6^x = b6

7^x = b7

8^x = b8

9^x = b9

10^x = b10

5. Now the fun part We calculate this:

c1 = b2 - b1;

c2 = b3 - b2;

c3 = b4 - b3;

c4 = b5 - b4;

c5 = b6 - b5;

c6 = b7 - b6;

c7 = b8 - b7;

c8 = b9 - b8;

c9 = b10 - b9;

6. Now we have the set of numbers c1..c9. We do the same and get the set d1..d8 (d1 = c2 - c1, d2 = c3 - c2 and etc.). We do this until we get a set of numbers that has equal numbers and if we decide to subtract again we will get 0. These equal numbers we will call Z.

7. Write here what value of x have you used and what Z have you got as answer?

P.S.

If all your calculations are correct you will have a Z that equals x!

*Last edited by krisper (2006-01-14 08:47:46)*

Humankind's inherent sense of right and wrong cannot be biologically explained.

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

That only works when x is a positive integer.

It's a nice pattern though. I played around with it, and discovered that you need to do Step 4. x times before you get your Z value. Also, if you're doing high values of x, you'll need more than 10 numbers to start off with.

*Last edited by mathsyperson (2006-01-14 11:28:29)*

Why did the vector cross the road?

It wanted to be normal.

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**krisper****Member**- Registered: 2005-12-20
- Posts: 19

Thanks for your reply mathsyperson.

And yes, you are correct and that why I said that x should be >=0 By the way I found this on my own a couple of years ago when I was playing of numbers hoping I will find something significant (everyone's dream ). It is very nice though, because when repeating the steps you will always get to the 0 value.

Humankind's inherent sense of right and wrong cannot be biologically explained.

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

It doesn't work with x=0 either. For that, you get a Z value of 1.

And my main point in the previous post was that x had to be an integer. If you take it as √ 2, then you'll get all kinds of odd numbers. They won't ever reach 0 either. At least, I don't think they will.

Why did the vector cross the road?

It wanted to be normal.

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**krisper****Member**- Registered: 2005-12-20
- Posts: 19

When is 0 you will get Z=1 and 0! equals 1, so n can be 0 And you are right again, it is only for integers because n! formula can only be used for integers that are >=0.

P.S. I have edited my first post telling that x must be integer

*Last edited by krisper (2006-01-14 08:48:45)*

Humankind's inherent sense of right and wrong cannot be biologically explained.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,659

From Excel:

```
x=4
1 1
2 16 15
3 81 65 50
4 256 175 110 60
5 625 369 194 84 24
6 1296 671 302 108 24 0
7 2401 1105 434 132 24 0
8 4096 1695 590 156 24 0
9 6561 2465 770 180 24 0
10 10000 3439 974 204 24 0
```

And for x=5 you need an extra column to reach 0

And it is fun to play with real values of x

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

krisper wrote:

When is 0 you will get Z=1 and 0! equals 1, so n can be 0

Oh! Sorry! When I read your original thing about Z=x!, I inferred that that was an exclamation mark, but now after reading MathsIsFun's post I realise that it was actually a factorial sign. Sorry again!

Why did the vector cross the road?

It wanted to be normal.

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