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## #1 2012-11-27 21:26:01

sulley
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### Massive Numbers

Hello all,

I was hoping you would be so kind as to help me with a problem that I'm having. I would like to calculate 141^(162^164), but the result is rather large and exceeds the capabilities of any software I have yet encountered.

I've tried using BC (see en.wikipedia.org/wiki/Bc_programming_language), you probably know that it's a very capable arbitrary precision calculator, but it can't manage it, it tells me that the 'exponent is too large in raise'.

Does anyone have any ideas? Do I have any chance of producing an actual result?

It's might be worth telling you that I know C, so can write some code to help, but the issue I have is that the types available in C aren't big enough, so I wouldn't even know where to start.

Thanks,

Rob

## #2 2012-11-27 21:52:25

bobbym

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### Re: Massive Numbers

Hi sulley;

Welcome to the forum!

The front part 16870151161094535473499554809767331400820946875159,,, called the mantissa is the first 50 digits of the number if you need more let me know.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #3 2012-11-27 22:05:24

sulley
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### Re: Massive Numbers

Wow, impressive! Thank you very much. Can you share how you did it please?

## #4 2012-11-27 22:08:45

bobbym

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### Re: Massive Numbers

There are a couple of ways of tackling tower problems as these are called.

There are math programs that can handle this large a  number directly.
Both Maxima using the BFloat class and Derive 6.1 are capable of getting this answer and I used Derive 6.1 to check.

There is a math way but it is a bit complicated if you have never seen it before.
Are you interested?

If you think that number is massive then think again:

that's massive^massive. 10 or more years ago I went after the front digit of that number. I was a mere lad of only 82 years of age so I figured I would bring it to its knees before I died...

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #5 2012-11-28 01:23:24

anonimnystefy
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### Re: Massive Numbers

You never told which digit was actually the first one...

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #6 2012-11-28 06:56:28

bobbym

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### Re: Massive Numbers

For the tower problem? I do not know which one it is.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #7 2012-11-29 01:36:44

sulley
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### Re: Massive Numbers

#### bobbym wrote:

There is a math way but it is a bit complicated if you have never seen it before.
Are you interested?

Yes it would interest me, but realistically I will have very little use for the knowledge, so I won't take any more of your time.

#### bobbym wrote:

that's massive^massive. 10 or more years ago I went after the front digit of that number. I was a mere lad of only 82 years of age so I figured I would bring it to its knees before I died...

Doesn't that make you 92? Or am I missing something.

Thanks again for you help,

Rob

Last edited by sulley (2012-11-29 01:37:10)

## #8 2012-11-29 02:33:21

bob bundy
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### Re: Massive Numbers

Or am I missing something.

Yes!  bobbym regularly lies about his age.

As far as I know only three people know for sure, and two of those are doubtful.

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #9 2012-11-29 03:09:54

anonimnystefy
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### Re: Massive Numbers

Well, he has given us some info about his age. He was born on the 3rd of July and on Sunday...

Last edited by anonimnystefy (2012-11-29 03:10:48)

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #10 2012-11-29 04:29:26

bob bundy
Moderator

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### Re: Massive Numbers

Is that reliable information though?

Bob

You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

## #11 2012-11-29 06:20:44

anonimnystefy
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### Re: Massive Numbers

I think so.

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #12 2012-11-29 06:34:46

bobbym

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### Re: Massive Numbers

Hi sulley and all;

I was not born in July. Records of my birth have been destroyed. Hospital burned down and so did the rectory.

Yes it would interest me, but realistically I will have very little use for the knowledge, so I won't take any more of your time.

Then it will die with me. It does appear I am 92 but no one believes that so sometimes I am younger.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #13 2012-12-06 04:26:53

sulley
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### Re: Massive Numbers

I'm back again! Is that 92 in hex?

I have an even bigger challenge for you, would you be so kind as to calculate 141!^(162!^164!) for me please? to as large an accuracy as you dare! (ridiculous,  I know!)

Thanks,

Rob

## #14 2012-12-06 07:44:19

bobbym

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### Re: Massive Numbers

Hi;

That is 92 in decimal. Your question boils down to this:

which means it is larger than my current limit of 9^(9^(9^5)). As a matter of fact
it is larger than 9^(9^(9^(9))) which I have struggled with for more than 10 years.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #15 2012-12-06 08:00:48

anonimnystefy
Real Member

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### Re: Massive Numbers

Hi bobbym

Is there a way to get the front digits of a number other than the one you showed me in the big Oh thread?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #16 2012-12-06 08:05:11

bobbym

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### Re: Massive Numbers

Hi;

That is the only one that I use consistently. Of course there are other methods but they are all experimental.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #17 2012-12-06 08:07:36

anonimnystefy
Real Member

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### Re: Massive Numbers

Do you know any?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #18 2012-12-06 08:10:40

bobbym

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### Re: Massive Numbers

This suggests another method but in this case it fails. As a matter of fact it fails for
9^(9^(9^9))) too! His number is just too large.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

## #19 2012-12-06 08:32:38

anonimnystefy
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### Re: Massive Numbers

I meant-do you have another method for evaluating those kinds of numbers in general, for example, less than 9^9^9^5?

The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

## #20 2012-12-06 08:43:51

bobbym

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### Re: Massive Numbers

Hi;

For 9^9^9^5 ( I leave out the bracketing from now on ) is a major undertaking and I used a
recurrence.

And you missed my point, post #18 does suggest another way.

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.