Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20121202 18:49:51
Is this inequation correct?Is this step of this inequation is correct,I got it from a book and I guess its wrong or may be I am missing something How come the sign changed? To me it doesnt make any sence. Thanks Debjit Roy ___________________________________________________ The essence of mathematics lies in its freedom  Georg Cantor #2 20121202 19:14:11
Re: Is this inequation correct?Hi debjit625; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20121202 19:14:17
Re: Is this inequation correct?It's wrong. The sign should've stayed the same... The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment 