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#1 2012-11-30 18:00:36

mathaholic
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Can U solve this?

Make 100 using the numbers 400, 200, 50 and 2.
Use the operations + - * / 2 (square) 3 (cube).

smile


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#2 2012-11-30 18:09:47

bobbym
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Re: Can U solve this?

Hi;



Welcome to the forum.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#3 2012-12-01 01:45:22

anonimnystefy
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Re: Can U solve this?

400-200-2*50=100


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#4 2012-12-01 12:12:26

mathaholic
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Re: Can U solve this?

Bobbym and anonimnystefy, you are both correct!
Now, second equation using PEMDAS:
Make 75 using the numbers 5 5 3.
Use the operations + - * / 2 3.


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#5 2012-12-01 19:15:32

bobbym
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Re: Can U solve this?

5 * 5 * 3 = 75


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#6 2012-12-01 21:22:51

mathaholic
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Re: Can U solve this?

Correct, bobbym! Anymore solutions?
sleep:


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#7 2012-12-01 21:41:03

bobbym
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Re: Can U solve this?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#8 2012-12-01 22:32:49

anonimnystefy
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Re: Can U solve this?

(5^2)^2/5^2 *3=75


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#9 2012-12-01 23:29:22

mathaholic
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Re: Can U solve this?

Great!
What about this?
Numbers 1 2 3
Operations + - x / 2 3
Answer 10
sleep sleep sleep sleep sleep sleep sleep sleep sleep


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#10 2012-12-01 23:36:51

bobbym
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Re: Can U solve this?

(2^3) + ( 3 -1 ) = 10


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#11 2012-12-02 11:53:56

mathaholic
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Re: Can U solve this?

Wow, bobbym! Anymore solutions?
sleep


246 pages on Prime Numbers Wiki (+1)
 

#12 2012-12-02 12:18:12

anonimnystefy
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Re: Can U solve this?

3^2+2-1


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#13 2012-12-02 12:19:25

mathaholic
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Re: Can U solve this?

Okay!


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#14 2012-12-18 22:15:55

mathaholic
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Re: Can U solve this?

New:
Answer 10000
Numbers 100 100 1
Operations + - x / 2 3


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#15 2012-12-18 22:48:22

bobbym
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Re: Can U solve this?

Hi;


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#16 2012-12-19 22:26:04

mathaholic
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Re: Can U solve this?

roflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflolroflol:

Last edited by julianthemath (2012-12-19 22:26:44)


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#17 2012-12-22 19:40:13

mathaholic
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Re: Can U solve this?

Okay.
Tricky!
Answer 120
Numbers 5 4 3 2 1
Operations 2 3 !


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#18 2012-12-22 19:56:51

bobbym
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Re: Can U solve this?

Hi;

(3+2)!


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#19 2012-12-22 22:11:54

mathaholic
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Re: Can U solve this?

Yurp.
Could


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#20 2012-12-22 22:13:53

bobbym
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Re: Can U solve this?

Could also be ( 1 + 4 )! or (( 5 + 4  +1 ) / 2)!


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#21 2012-12-22 22:20:50

phrontister
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Re: Can U solve this?

And could also be 1! x 2 x 3 x 4 x 5


"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson
 

#22 2012-12-22 22:28:22

bobbym
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Re: Can U solve this?

Hi julianthemath;

I missed that you only wanted the operations of factorial and 2 and 3.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#23 2012-12-25 12:58:58

mathaholic
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Re: Can U solve this?

Okay!
Numbers 8 7 6 5 4 3 2 1
Operations 2 3 !
Answer 40,320


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#24 2012-12-25 14:16:11

muxdemux
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Re: Can U solve this?

How do you do one of those spoiler tags?

Anyway, am I playing this game right?

(8!/7!)*(7!/6!)*(6!/5!)*(5!/4!)*(4!/3!)*(3!/2!)*(2!/1!)

 

#25 2012-12-25 16:23:54

mathaholic
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Re: Can U solve this?

Muxdemux, belated welcome to the forum.
Are you sure that is right? I will post a new one soon.


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