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**BarandaMan****Guest**

Ok thanks I got the same as you when I just expanded this.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 103,717

Hi;

You do not need to copy my posts. It is not necessary and it is extra work.

Take the first equation and solve for q^H. You get:

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**BarandaMan****Guest**

Shouldn't it be 3b-ub on the bottom ?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 103,717

Hi;

No, we are not done yet. I just solved for q^H, it is not the final answer.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**BarandaMan****Guest**

I know, but on the thing you posted, the denominator you got ub-3b and I have 3b-ub

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 103,717

You should notice that I have a q^L in the partial answer. That is because it is not done yet.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**BarandaMan****Guest**

I know we are not done, but on the expression you just posted for qh.... at the bottom you have b(u-3) and I get b(3-u), this is what I am talking about.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 103,717

You mean on the step I just did or on the final answer?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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**BarandaMan****Guest**

bobbym wrote:

You mean on the step I just did or on the final answer?

On the step you just did

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 103,717

Could just be a sign change. Let me see your answer.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**

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