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Hi;
Can you differentiate this wrt Pi?
It is just a power rule.
So I think this would become nWYP^n-1Pi^-n+1?
Can we write that in a nicer way?
Hi;
That is not correct but it is close. After we move all the constants to the left you are differentiating:
Please differentiate that right now.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi;
That is not correct but it is close. After we move all the constants to the left you are differentiating:
Please differentiate that right now.
That is I think -nPi^-n+1?
Please use brackets.
What is the power rule?
Differentiate that please.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Please use brackets.
What is the power rule?
Differentiate that please.
Sorry: (-n)(Pi)^(-n+1)
Erm I do not know, I think that is just simply 2x once differentiated? Multiply across then subtract the one?
(-n)(Pi)^(-n+1)
That is not correct. Just follow the formula.
Power rule:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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(-n)(Pi)^(-n+1)
That is not correct. Just follow the formula.
Power rule:
Ok, thank you.
Is that not what I did with x^2? Differentiate it and you get 2x? because 2x^(2-1) = 2x^1 = 2x?
Yes, you were right for x^2 but wrong for Pi^(-n) which means you are not using the power rule or you are using it incorrectly.
Now, please differentiate this using the power rule:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, you were right for x^2 but wrong for Pi^(-n) which means you are not using the power rule or you are using it incorrectly.
Now, please differentiate this using the power rule:
AHHHH! I get this, I think! So it is -nPi^(-n-1) and before I was adding one!?
That is correct! You have one more part to do.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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That is correct! You have one more part to do.
YAY! Thank you!
SO, in whole must become, nWYP^(n-1)Pi(-n-1)? (For the bit you asked about before? )
nWYP^(n-1)Pi(-n-1)?
You left out an exponentiation sign in there.
It is Pi^(-n-1).
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ah yes thank you bobby, sleep eyes.
Now this term is complete? But when you posted a solution, you had (nWY((Pi/P)^(-n-1)))/P^2 ? How did you get from the differentiated thing to this for this specific term?
There is one more term to be differentiated. When we simplify it all up we will see.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ok great! Now the last term, want to differentiate (YPi((Pi/P))^(-n))/P. So for this I get (-nYPi(Pi/P)^(-n-1))/P, but I know this is wrong because there are two Pi's and I am only doing one of them, how does this work??
Hi;
We are not done yet, not by a long shot. Which term are we working on?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The last term!
I think when we differentiate it we get (-nYPi((Pi/P)^(-n-1)))/P?
The third term has a P in the denominator. I left it out because we concentrated on the numerator. So we are not done with the third term.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The third term has a P in the denominator. I left it out because we concentrated on the numerator. So we are not done with the third term.
I see, apologies for not making this clear: P and Pi are completely different things.... P could be Y or X for example! It just happens to represent something beginning with P! But Pi is what we want to differentiate with respect to!
We differentiated that when the real problem is this:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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OH, so hwo do we do it?
oh my god why is this so difficult for such a little step, can we please go through this.
Since the P is a constant just take the answer you got and put it over P.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Since the P is a constant just take the answer you got and put it over P.
Ok now I am just getting confused, so that answer I had was correct?
Ok let's just leave this I don't think I can solve this problem anymore. Thank you though.
Hi;
Okay, but we are almost done with the whole problem and are done with the third term.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Is there anyone here who can actually help me by explaining this methodically and quickly?
I have exams approaching in January and tried to solve this problem weeks ago. I cannot do it. I do not have the time to spend another 2 weeks trying to be directed to a correct answer. I have memorised the solution so that will be fine (solution is posted), but I do not understand how to differentiate it. Please help me.