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**BarandaMan****Guest**

Equation 1 has p1 and p3 in.

Equation 2 has p2 and p3 in.

Equation 3 has p1, p2 and p3 in.

This is highest priority in terms of my work as I think it will help me solve one of the other questions I have posted up. Will refresh every 5 minutes so am here to discuss! Thanks you all

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

What are the equations?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

Will it be easier if I right in neat on paper and then upload picture for you bobby? Or easier for you if I write on here in the (messy) way?:P

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

Post it here. Use lots of spaces for clarity and brackets.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

(4 - P3) /2 = P1

(6 - P3) /2 = P2

P3 = (10 - 0.5P1 - 0.5P2) / 2

i47.tinypic.com/97vbwk.jpg - JUST incase my writing is uncomprehendable!

What I have tried is to put the expression for P3 into the first equation, this led me to get P2=3P1+12

I then tried to put the expression for P3 into the second equation, this led me to get P1=3P2+8

I then P1=3P2+8 into P2=3P1+12 and I got from this, that P2=-4.5? Which is wrong I assume only because the question specified P>0 (since P= price), so I must have gone wrong I think!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

Is the the system you want solved?

P1 = - ( 1 / 2 )

P2 = 1 / 2

P3 = 5

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

Oh my god?! How did you do that? This is incredible. Apologies for the delayed response, internet went down for over an hour.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

Do you know how to use substitution?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

bobbym wrote:

Hi;

Do you know how to use substitution?

I think so, that's what I tried but I always got it wrong!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Did you use equation 1 and substitute for P1 into equation 3?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

bobbym wrote:

Did you use equation 1 and substitute for P1 into equation 3?

I tried substituting everything into everything, I keep going round in circles and have two unknowns in every equation. But this can be done apparantly it shouldn't be too difficult. I just cannot see it.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

From the first equation you get

You substitute for P1 in equation 3. That gives 2 equations with 2 unknowns. Can you solve now?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

Wait I think I just did it, i got p1 = -1/2. We cannot have a negative price so I won't solve for p2 and p3 yet, I must have done something wrong earlier. This is awful I will not be asleep for a while.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

P1 = ( - 1 / 2 ). If that does not fit then you have set the problem up wrong.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

THANK you for guiding me on this. Please don't waste your time here, I will go over this freshly again and see what I have done wrong. I HAVE to get to a stage with three equations in three unknowns, it just means my numbers were wrong earlier because a negative price cannot happen in this particular question, but thanks to you at least i can solve three equations in three unknowns!

Maths is SO stressful sometimes and i try SO hard, i am really good at mental maths but as you can see I am poor at most else, it really drags because i want to do well. thank you again for your help bobby.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

Maths is SO stressful sometimes and i try SO hard,

Math is hard work for everybody. Go over how you set the problem up there is certainly a mistake there.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

DONE IT!!!

Basically, I missed out a '2p2' a LOT earlier on, I went through it all over and wrote it again and I was like, where did that 2p2 dissappear?! (I forgot it off one line of algebra)...went through everything and the end three equations were very simple thanks to your guidance. Thank you again. LOVE it when it works!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Your work looks like you are doing some kind of physics. You have my sympathy...

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

I am doing a bit of EVERYTHING!

What did you specialise in??

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Unfortunately at one time I loved physics and group theory. I actually thought I was doing mathematics... Then like Saul, I was struck by lightning and saw the light. Computational mathematics!

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**BarandaMan****Guest**

bobbym wrote:

Unfortunately at one time I loved physics and group theory. I actually thought I was doing mathematics... Then like Saul, I was struck by lightning and saw the light. Computational mathematics!

Hahahaha! That is brilliant!