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You are not logged in. #1 20121118 12:16:52
New mathematic on englishONE OF MANY ERRORS IN CALCULUS. For a justification of that the not proof the formula which contradicts established rule was entered, because . To show that antiderivative isn't the one of family of antiderivatives , because equal full and partial derivatives isn't the basis for complete identification of two different orocess of their receiving, I will give argument and proof. Argument: 1. . For integration of a partal derivative it is nessesary to use indefenite integral . 2. . For integration of a full derivative it is necessary to use integral with indefinite borders of integration . 3.  incorrectly,  true. Proof: WE INVESTIGATE FUNCTION, WITH THE CONSTANT OF INTEGRATION EQUAL TO ZERO, FOR THIS PURPOSE, TO PROVE ITS SEPARATE CASE OF ANTIDERIVATIVE NOT ENTERING INTO FAMILY WITH NONZERO CONTANTS OF INTEGRATION ! Integral application for a case of (1) leads to its such look: . (2) ;  contradicts (2) ATTENTION ! according a statement of the problem! P.S. It is translated by means of the robot Last edited by 21122012 (20121119 10:14:13) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #2 20121119 05:50:44
Re: New mathematic on englishBut "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #3 20121119 09:56:21
Re: New mathematic on english"a" in relation to the variable "x"  is a constant, but in relation to the "D"  is a variable ! Last edited by 21122012 (20121119 10:19:58) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #4 20121119 11:28:11
Re: New mathematic on englishIf D is a function of a constant than it is a constant. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #5 20121119 13:45:20
Re: New mathematic on englishYou don't understand that such a constant. This concept not absolute, but relative. Look in this drawing and  in one case of a constant, as values of the variable , in other case  variable arguments of their sum.//vladimir938.etoya.com/files/2012/11/screenshot19.11.jpg "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #6 20121119 13:49:41
Re: New mathematic on englishWhat matters in integration is that the constant C is independent of the variable of integration. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #7 20121119 15:32:00
Re: New mathematic on englishI don't understand what you want. In the starting message it is shown that is used antiderivative with a constant equal to zero. C=0, D=0, E=0...Z=0, A=0, B=0. You understand?! Last edited by 21122012 (20121119 15:34:12) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #8 20121119 17:38:37
Re: New mathematic on englishYes, but, for what reason is C=0? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #9 20121119 17:50:27
Re: New mathematic on english
Read startpost. "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #10 20121120 05:38:14
Re: New mathematic on englishTo BOB BUNDBY: You don't understand that about what I want to tell This formula is true for antiderivatives for example: agrees CALCULUS. I argue that from these all formulas one which doesn't approach under the general rule is allocated: You understand? "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #11 20121120 05:51:29
Re: New mathematic on englishBecause: But: Last edited by 21122012 (20121120 05:56:29) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #12 20121120 06:44:41
Re: New mathematic on englishIn the last line of the proof I show that for equality preservation in an integration formula in parts, function with an integration constant can be antiderivative only. Antiderivative without an integration constant (i.e. with a constant equal to zero), breaks equality of the right and left part of a formula. ANTIDERIVATIVE WITHOUT the CONSTANT of INTEGRATION Last edited by 21122012 (20121120 06:48:01) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #13 20121120 11:11:27
Re: New mathematic on english
Using the partial derivative operator is used for derivatives of functions of arity 2 and more. I do not see 2 let alone more than 2 parameters in those functions... Last edited by anonimnystefy (20121121 09:01:07) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #14 20121120 12:32:52
Re: New mathematic on englishStudy a partial derivative. Last edited by 21122012 (20121120 12:34:48) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #15 20121120 14:28:18
Re: New mathematic on englishHi;
That is not quite enough.
Since you are disagreeing with the entire mathematical community both present and past, the onus is on you to provide solid evidence to convince everyone else. You will have to point out where anonimnystefy is going wrong. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #16 20121120 16:40:57
Re: New mathematic on englishHi. I do not understand sense which translates me the robot: Last edited by 21122012 (20121120 16:41:50) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #17 20121121 08:11:03
Re: New mathematic on english
Here "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #18 20121121 10:55:34
Re: New mathematic on englishHey that is a forum I did not know about. That is still not authoritative proof. Unfortunately you have to submit your ideas to a recognized journal for peer review for the mathematical community to listen. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #19 20121121 11:11:36
Re: New mathematic on english
Now, after correction, the robot translated correctly! "C"  it is the general image of all expressions which are not depending from "x", including parameters. Therefore I also suggest to enter two formulas of integrals. "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #20 20121121 11:14:25
Re: New mathematic on english
I don't know as it to make. If you prompt, I will be grateful to you. But I have no sponsors. "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #21 20121121 11:34:38
Re: New mathematic on englishHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #22 20121121 11:57:20
Re: New mathematic on english
Clearly. I do that while is available to me. Your site is in Great Britain. In London there lives the Russian mathematician and the businessman [removed by administrator]. You don't know as I can begin with it correspondence? "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #23 20121121 13:36:57
Re: New mathematic on englishHi; That is a rule, they call them definitions. I do not debate about definitions any more than I question why the knight moves as it does. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #24 20121122 05:31:22
Re: New mathematic on englishWell, close this subject. I should open new and to give in it a material which I for the present didn't want to give. But it is necessary. Probably you will prompt me one more of sites in U.S.A. in where I too can place the new message. Last edited by 21122012 (20121122 05:32:04) "The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus" Thomas Ioannes Stiltes. ... I made it! #25 20121122 09:26:34
Re: New mathematic on englishHi 21122012; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 