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You are not logged in. #1 20121113 06:36:32
dimension of a subspacelet V be a vector space of all polynomials with real coefficients with degree at most n where n>=2, consider the elements of V as a function from R to R. define W={p belongs to V∫egration 0 to 1 p(x) dx=0} , show thar W is a subspace of V and dim W= n. #2 20121113 12:14:15
Re: dimension of a subspaceLet where . Then . This suggests that a basis for is . All you have to do is to prove it. NB: I've just shown that the set spans W; it remains for you to prove that it's linearly independent. Last edited by scientia (20121113 12:19:04) 