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**BarandaMan****Guest**

9pq < 6pq +6(1-p)(1-q). Implying that 3pq/(1-p)(1-q) < (less than or equal to) 2

PLEASE explain this somebody! I don't understand how this works? Does it not equal 3<6(1-p)(1-q)?

Please walk me through this. Thanks.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,248

Hi BarandaMan;

Do you mean

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

Yes I do! That is what the answer says but i do not understand how it gets past the 'implies' after rearranging

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,248

Hi;

Subtract 6pq from both sides.

Divide both sides by 3.

Divide both sides by (1-p)(1-q) provided that p,q are both less than 1.

I do not know where the 3 comes from in your question.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

Hey!

That is exactly what I got! Thank you. That is why I am confused, because the 3pq I posted it in the ANSWER BOOK. Which is why I am confused by this!

It cannot be the answer from the inequality!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,248

Hi;

The answer book? What is that?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**BarandaMan****Guest**

I did the question from a book, and in the back ith as the answers. The first line of my original post shows what the answer is in the textbook. It must be wrong, I will write a letter. It is simple inequality I thought... must be printing error.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,248

I would think it is a typo.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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