Start with 2 baby rabbits, 1 male and 1 female. These baby rabbits became adult rabbits the next month. The month after that they produce a pair (one male, one female) of baby rabbits. Now in each subsequent month, each pair of baby rabbits reaches adulthood and each pair of adult rabbits produces a new pair(one male, one female) of baby rabbits.
Hence, the Fibonacci sequence 1, 1, 2, 3, 5, 8, 13, 21,...
Question: How many pairs of rabbits will there be after n months?
Explain why the answer is F(subn).
Any help would be much appreciated.
Welcome to the forum.
You should find all you need here:
There are also some good poages on the MIF site:
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Welcome to the forum. To get Fn you must be able to solve the recurrence for the Fibonacci sequence. You can use the characteristic polynomial to do that.
If it ain't broke, fix it until it is.
No great discovery was ever made without a bold guess.