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You are not logged in. #1 20121107 18:49:37
finding limit((1+cx)/(1cx))^(1/x) tends to 4 as x tends to infinity. #2 20121107 19:41:28
Re: finding limitHi princess snowwhite;
I can not find any c that will give 4 as x approaches infinity. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20121108 00:46:26
Re: finding limitThe first limit is 1 for every c. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #4 20121108 05:21:06
Re: finding limitHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20121108 06:20:27
Re: finding limitMaybe it is a misprint or a typo. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #6 20121108 06:27:03
Re: finding limitYes, it should read 1 instead of 4.
So the answer should be 1 because 2c=c. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20121108 07:25:20
Re: finding limitI don't think that is the misprint. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #9 20121108 07:36:30
Re: finding limitNot really. The question would be close to trivial. I think the question is more likely to be asking for the constant c for which a limit has the value 4 and then finding the same limit but with 2c instead of the c, whose value we now know. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #10 20121108 07:40:18
Re: finding limit
There is no c that will give a limit of 4. You said so yourself. The limit is independent of c. That is why it is trivial. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #11 20121108 07:45:48
Re: finding limitYes. So I am thinking that it might be a typo of the function whose limit is being taken. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #12 20121108 07:48:42
Re: finding limitMaybe the questioner just wants the OP to see that the answer is 1. To spot the inconsistency. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #13 20121108 07:53:17
Re: finding limitThis looks too much like a book problem. I do not think that is what it wants. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #14 20121108 07:55:33
Re: finding limitIsn't the simplest typo that she wrote 4 when she meant 1? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #15 20121108 08:00:10
Re: finding limitBeing simplest doesn't makng true. And, yes, I am familiar with the Occam's razor. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #16 20121108 08:01:57
Re: finding limitI use Schick's or Gillette's razor for a better shave. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #17 20121113 01:26:50
Re: finding limitHello! The answer is \lim_{x\to\infty }\left({{2\,{\it cx}+1}\over{12\,{\it cx}}}\right)^{{{1}\over{x}}} = 1. #18 20121113 05:29:24
Re: finding limithi mathteacher005 numberempire.com/limitcalculator.php?fu … =twosided Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei 