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You are not logged in. #1 20121031 07:05:04
[CALCULUS] Differentiation and rate of changes PROBLEMA block of ice, in the shape of a rectangular prism, has the dimensions give below: #2 20121031 07:16:19
Re: [CALCULUS] Differentiation and rate of changes PROBLEMIs it impossible to calculate if we dont know the width of the rectangular ice prism? #3 20121031 08:07:41
Re: [CALCULUS] Differentiation and rate of changes PROBLEM
alright, take ur time! thanks a lot!! #4 20121031 08:18:44
Re: [CALCULUS] Differentiation and rate of changes PROBLEMThanks for saying that. I'm having lots of trouble with this. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #5 20121031 08:26:30
Re: [CALCULUS] Differentiation and rate of changes PROBLEMCannot be for all time intervals or the amount of melting gets less and less and takes an infinite amount of time. ????? You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #6 20121031 08:37:43
Re: [CALCULUS] Differentiation and rate of changes PROBLEM
i can only use differentiation in this assignment!! So hard:mad: #7 20121031 09:00:03
Re: [CALCULUS] Differentiation and rate of changes PROBLEMOnly differentiation. eeekkkk! hence work out dV/dx using differentiation. You can also write an expression for the surface area in terms of x and hence write the rate of change of volume You should be able to work out both numbers. Stick a minus on this as the volume is decreasing. As x squared occurs in both of these you can get This will integrate to an expression like this m will be negative. Note x will be the vertical axis and t across. Use the initial volume and volume after one unit ot time to determine this gradient m. When does the line cut x = 0 ? That's my best shot I'm afraid. Maybe someone else on the forum will come in with a better suggestion. Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #8 20121031 09:01:51
Re: [CALCULUS] Differentiation and rate of changes PROBLEMI do not understand what the 3rd piece of information is. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #10 20121031 09:06:43
Re: [CALCULUS] Differentiation and rate of changes PROBLEM
3) is bothering me. From iit I gather that (V+dV)/V is equal to 1/39.5 in which case the block of ice is melting very rapidly. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #12 20121031 09:46:35
Re: [CALCULUS] Differentiation and rate of changes PROBLEMAnd c=x0. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #13 20121031 11:25:51
Re: [CALCULUS] Differentiation and rate of changes PROBLEMIf the width decreases linearly then the volume will decrease by the cube of the value of 'm' So maybe Does that help ? Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #14 20121031 12:17:06
Re: [CALCULUS] Differentiation and rate of changes PROBLEM
thanks, they are really helpful #15 20121101 19:25:53
Re: [CALCULUS] Differentiation and rate of changes PROBLEMHi Kevin123123, You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #16 20121101 20:13:55
Re: [CALCULUS] Differentiation and rate of changes PROBLEM
Again? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #17 20121101 22:00:45
Re: [CALCULUS] Differentiation and rate of changes PROBLEMYes, it forgot it had a wireless card. You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #18 20121108 20:16:04
Re: [CALCULUS] Differentiation and rate of changes PROBLEMHi, #19 20121109 00:07:22
Re: [CALCULUS] Differentiation and rate of changes PROBLEMhi Anonymous Subject to the usual rules about differentiability you can do this with any three related variables. Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei 