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**Leroy****Guest**

How do i solve these

5 mod 2+2i

4+5i mod 3

3+i mod 1+i

i mod 3

56 mod 5i

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,771

Hi Leroy;

For 5 mod 2+2i;

So the answer is 1.

For 4+5i mod 3;

So the answer is 1 - i.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**Leroy****Guest**

I didn't really understood the first method and it seems to me the second one could be (4+5i)-3(1+i)=1+2i

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,771

Hi;

That is not the correct expression. Mathematica confirms what I did in post #3.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**Ronald****Guest**

Ok,but could you explain the method to me?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,771

Hi;

I am just plugging into a formula:

For a mod n

I have been interpreting the int as the greatest integer.

I would say to be careful with the work done above. I can find no standardization for that formula for complex numbers. As a matter of fact some say floor or int are not defined for complex numbers. Others define them differently than Mathematica does.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

Interesting, I never thought about modular arithmetic with complex numbers.

**Leroy****Guest**

I think,as complex number is also a number,so it should have all properties of normal number-mod,factorial,floor,ceil,ratio,integer part,...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,771

Not necessarily, there are differences. For one thing the mod function is different.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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