Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**danthemaths****Member**- Registered: 2012-10-18
- Posts: 2

hey guys, I am stuck on this question:

"The Remainder when x^3-2x^2+ax+5 is divided by x-3 is twice the remainder when the same expression is divided by x+1. Find the value of the constant a."

I know the answer is 4 but i dont know how to get there.

I have started it off but dont know what to from then on...

I worked out f(3) to be -14=3a

...and f(-1) to be a=2

Am I on the right lines? and what do I do from then on? this will really help me out

thanks in advance

danthemaths

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 7,055

hi danthemaths

Welcome to the forum.

Am I on the right lines?

Not quite.

When you put x = 3 you get a remainder. Let's say

and when x =-1

You are also told that

So make an equation from this and solve for a.

Hope that helps.

?? But I'm not getting a = 4 ??

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

Pages: **1**