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**Sum of no.**

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**juan****Guest**

(1) The sum of all no. that can be formed by using the digits

(2) Total no. of positive Integer solution of

(3) Total no. of positive Integer solution of

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,236

For (1): Must all the digits be used in making one number?

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,294

Q1. There are 7 digits. Pretend they are all different, a,b,c,d,e,f,g say.

Find all the possibilities:

a, ab, abc, .......fg, g

Now allow for the repeats by dividing (eg if all 4s then divide by 4!)

Might be easier to count by taking all the 4s; then only three 4s then only two etc.

Q2. No number can be over 10 or under 1.

So 10 + 1 + 1

9 + 2 + 1

9 + 1 + 2

etc. It's not so bad to continue like this, is it?

That should show you a generating technique which will make Q3 easy.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,236

bob bundy wrote:

Q1. There are 7 digits. Pretend they are all different, a,b,c,d,e,f,g say.

Find all the possibilities:

a, ab, abc, .......fg, g

Now allow for the repeats by dividing (eg if all 4s then divide by 4!)

Might be easier to count by taking all the 4s; then only three 4s then only two etc.

Q2. No number can be over 10 or under 1.

So 10 + 1 + 1

9 + 2 + 1

9 + 1 + 2etc. It's not so bad to continue like this, is it?

That should show you a generating technique which will make Q3 easy.

Bob

We don't need the number of those kind of nos in tthe first problem. And in the second problem, the numbers an also take on a negative value...

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,285

Hi juan;

For 1)

I am getting 399999960. I am assuming you want to use all seven numbers to form a seven digit number.

For 2) I am getting 578.

For 3) I am getting 4672.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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