Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20120927 21:17:53
Interesting square problem (and a way to solve it)Hi guys! Yesterday I found a cool problem: Now, despite this is correct, I find it a little complicated, and I think that some calculations could be avoided. For example, could you show that GF=FE without explicitly calculating it as I did? Or, how would you show that BF lies on BD? In general, how would you solve the whole problem? edit: maybe a mod could put a spoiler on my solution... i don't know how to do that Hope you like this :) Last edited by Fistfiz (20120927 23:14:19) 30+2=28 (Mom's identity) #2 20120927 22:46:44
Re: Interesting square problem (and a way to solve it)Hi Fistfiz to get Last edited by anonimnystefy (20120927 22:48:05) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #3 20120928 01:17:35
Re: Interesting square problem (and a way to solve it)Hi Fistfiz; The area of the red shaded area is: Of course the area of the square with sides of length n is n^2. So the ratio of the BEFG to ABCD is 4 / 15. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #4 20120928 02:18:00
Re: Interesting square problem (and a way to solve it)Hi bobbym, thank you for your answer... 30+2=28 (Mom's identity) 