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**number0001****Member**- Registered: 2006-01-06
- Posts: 3

I got another trig problem, which is to prove (make the left side of the "=" equal to the right side).

(cos3x-cosx)/(sin3x-sinx)=-tan2x

I tried it but got stuck. Thanks very much for any help!

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**mikau****Member**- Registered: 2005-08-22
- Posts: 1,504

I could work it out myself but I think you should.

First I'd suggest replacing cos(3x) and sin(3x) with cos(2x + x) and sin(2x + x) then use the sum identities. We did this in the previous example. And note the identity tan (2x) = (2 tan x)/(1 - tan^2 (x) ). Also note that tan x = (sin x)/(cos x)

You can do it!

A logarithm is just a misspelled algorithm.

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**mikau****Member**- Registered: 2005-08-22
- Posts: 1,504

Also note the identiy for sin(2x) and the three identities for cos(2x).

I'd really really really reccomend printing out a reference sheet of all the indentities. I have a binder of lots of difference indentities and math notes. This is math, not spelling. Understanding why a formula works is more important then remembering it. Just print out a reference sheet.

A logarithm is just a misspelled algorithm.

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**mikau****Member**- Registered: 2005-08-22
- Posts: 1,504

If you really can't get it I'll explain how to do it, but you really ought to learn to do this for yourself. I wouldn't really be helping you if I just did the problem for you.

A logarithm is just a misspelled algorithm.

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