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#26 2012-07-22 05:45:44

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,319

Re: a challenging problem for all

If you meant an expression for the closed form then it is obviously not possible. The sum will either equal a constant or infinity.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

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#27 2012-07-22 05:47:03

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,522

Re: a challenging problem for all

It is possible.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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#28 2012-07-22 05:49:48

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,319

Re: a challenging problem for all

With a variable as the upper index yes. But with an infinity up there the sum is either a constant like 1 / 2 ( just picked as an example ) or ∞.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

Online

#29 2012-07-22 05:52:02

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,522

Re: a challenging problem for all

It can be an expression in terms of x.


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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#30 2012-07-22 09:01:52

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,319

Re: a challenging problem for all

Yes, it could.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

Online

#31 2012-08-15 01:05:45

rajinikanth0602
Member
Registered: 2012-06-30
Posts: 16

Re: a challenging problem for all

hi bobbym any information about my question

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#32 2012-08-15 01:35:48

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,319

Re: a challenging problem for all

Hi rajinikanth0602;

By the ratio test:

By the ratio test the series diverges for all values of x.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

Online

#33 2012-09-01 21:17:30

rajinikanth0602
Member
Registered: 2012-06-30
Posts: 16

Re: a challenging problem for all

i think post reply ''19'' is not correct

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#34 2012-09-01 21:18:23

bobbym
Administrator
From: Bumpkinland
Registered: 2009-04-12
Posts: 86,319

Re: a challenging problem for all

Hi;

Did you see post #32?

i will challenge that i will give 7000 rupees for solving dis problem or any important information about that sequence or range of that sequence

In exchange for the rupees I would like your acknowledgement that the problem has been solved with the proof that is in post#32, or do you require more?

As for post #19. It may be correct, I do not know. Still it is a very nice piece of work by a good man.


In mathematics, you don't understand things. You just get used to them.
Of course that result can be rigorously obtained, but who cares?
Combinatorics is Algebra and Algebra is Combinatorics.

Online

#35 2012-09-01 23:05:52

anonimnystefy
Real Member
From: The Foundation
Registered: 2011-05-23
Posts: 15,522

Re: a challenging problem for all

Hi rajinikanth0602

What problems do you see in post #19?

Last edited by anonimnystefy (2012-09-01 23:06:11)


“Here lies the reader who will never open this book. He is forever dead.

“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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