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#1 2012-08-24 10:11:42

anonimnystefy
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A custom Maxima Riemann sum function

Code:

integraten(f,a,b,n):=sum(ev(f,x=a+i*(b-a)/n)*(b-a)/n,i,0,n-1);

Last edited by anonimnystefy (2013-04-19 10:13:46)


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#2 2012-08-25 07:00:01

bobbym
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Re: A custom Maxima Riemann sum function

Hi;

What does ev do?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#3 2012-08-25 07:02:56

anonimnystefy
Real Member

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Re: A custom Maxima Riemann sum function

ev(expresson in x, x=value) evaluates the expression at a specified value of the variable x (or any variable which the expression is given with).


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#4 2012-08-25 17:33:46

bobbym
Administrator

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Re: A custom Maxima Riemann sum function

Hi anonimnystefy;

Nice, but please correct this line in your function:

Code:

s:s+ev(f,x=i)*(a-b)/n,

In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#5 2012-08-25 20:09:12

anonimnystefy
Real Member

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Re: A custom Maxima Riemann sum function

Oh yeah. It should be b-a there.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#6 2012-08-25 20:23:56

bobbym
Administrator

Offline

Re: A custom Maxima Riemann sum function

Hi;

That is exactly right.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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