Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20120808 11:26:11
IntegrationHi, #3 20120808 22:49:38
Re: IntegrationHi Bob;
You could have chosen as the factorization. Now the result follows. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #4 20120809 02:56:48
Re: IntegrationThanks bob bundy and bobbym. and told to use polar coordinates. I was confused on how to go from the above function to a function of x and y. Last edited by careless25 (20120809 02:57:09) #5 20120809 04:01:28
Re: IntegrationHad me stuck too. But I found this: You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #6 20120809 04:16:10
Re: IntegrationHahaha I could not have thought of that on the final exam. Lost 10% right there . #7 20120809 08:34:05
Re: IntegrationHi Bob bundy, now from here convert to polar coordinates EDIT: I am not sure what the integration limits for theta would be...if it is 0 to pi/2, then this works out. let u = r^2, du = 2rdr since we squared the original equation, we square root the final answer so This doesnt agree with what wolfram and wikipedia get . Any idea where I went wrong? Thanks Last edited by careless25 (20120809 09:25:31) #8 20120809 09:52:18
Re: IntegrationI have been looking at this and I realized that if we just square the actual integral and dont use the fomula given to us, we get to the correct answer. but this does: Last edited by careless25 (20120809 09:53:00) #9 20120809 20:31:02
Re: Integrationhi careless25 You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei 