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#1 2006-01-06 03:45:39
- Math Student
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A Miscellaneous Problem that I can't work out!
Please help me on this question!
24 unit cubes can be stuck together to make cuboids of different shapes. How many DIFFERENT cuboids can be made?
How many different cuboids can be made with:
a) 56 cubes
b) 100 cubes
Thanks In Advance!
#2 2006-01-06 03:48:00
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Re: A Miscellaneous Problem that I can't work out!
In fact, there is another question:
Many small cubes of side 1.2 are stuck together to make a large cube of 216cm³.
How many cubes are needed.
I worked it out to be 125 but can anyone confirm that answer?
#3 2006-01-06 06:01:53
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
1x1x24
1x2x12
1x3x8
1x4x6
2x2x6
2x3x4
6 combinations.
IPBLE: Increasing Performance By Lowering Expectations.
#4 2006-01-06 06:02:53
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
56=7x8
1x1x56
1x7x8
2 combinations
IPBLE: Increasing Performance By Lowering Expectations.
#5 2006-01-06 06:04:29
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
100=5x5x4
1x1x100
1x4x25
1x5x20
4x5x5
4 combinations
IPBLE: Increasing Performance By Lowering Expectations.
#6 2006-01-06 06:08:55
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
Let there be x cubes. the volume of each is 1.2^3=1.728 =>
x=216/1.728
x=125 cubes.
IPBLE: Increasing Performance By Lowering Expectations.
#7 2006-01-06 06:14:22
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
you're absolutely right!
IPBLE: Increasing Performance By Lowering Expectations.
#8 2006-01-06 06:26:13
- mathsyperson
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Re: A Miscellaneous Problem that I can't work out!
There are a few more combinations for 56 and 100, because 8 and 4 can be broken down more.
56 = 2x2x2x7
1x1x56
1x2x28
1x4x14
1x7x8
2x2x28
2x4x7
6 combinations.
100 = 2x2x5x5
1x1x100
1x2x50
1x4x25
1x5x20
1x10x10
2x2x25
2x5x10
4x5x5
8 combinations.
Why did the vector cross the road?
It wanted to be normal.
#9 2006-01-06 06:37:17
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
you're absolutey right!
IPBLE: Increasing Performance By Lowering Expectations.
#10 2006-01-06 06:38:31
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
Can we find formula for this?
IPBLE: Increasing Performance By Lowering Expectations.
#11 2006-01-06 06:39:33
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
If n is prime we have only 1 combination:
1x1xn
IPBLE: Increasing Performance By Lowering Expectations.
#12 2006-01-06 06:41:24
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
If n is product of two prime we have 2 combinations:
1x1xn and
1xp1xp2
IPBLE: Increasing Performance By Lowering Expectations.
#13 2006-01-06 06:42:45
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Re: A Miscellaneous Problem that I can't work out!
Wow! Thank you for your help!
#14 2006-01-06 06:43:44
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
I thought out an algoritm that can be used
IPBLE: Increasing Performance By Lowering Expectations.
#15 2006-01-06 07:03:21
- mathsyperson
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Re: A Miscellaneous Problem that I can't work out!
Be careful, though. As we can see from the example above, how many prime factors a number has isn't the only thing it depends on.
56 and 100 both have 4 prime factors, but they give answers of 6 and 8.
Why did the vector cross the road?
It wanted to be normal.
#16 2006-01-06 07:12:12
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
Yes, I saw that. My first result:
Ler dq[x] gives the number of the different divisors of x. Then the number of diffrerent rectangles that can be made with n squares is
Ceiling[dq[x]/2]
Last edited by krassi_holmz (2006-01-06 07:16:23)
IPBLE: Increasing Performance By Lowering Expectations.
#17 2006-01-06 07:15:16
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
Example:
number:36
divisors:1,2,3,4,6,8,9,12,18,36
dq[36]=10
So we must have 5 rectangles. Here are they:
1x36
2x18
3x12
4x9
6x6
IPBLE: Increasing Performance By Lowering Expectations.
#18 2006-01-06 07:27:14
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
Here is it in Mathematica language:
dq[x_] := Ceiling[Length[Divisors[x]]/2]
IPBLE: Increasing Performance By Lowering Expectations.
#19 2006-01-06 07:32:34
- krassi_holmz
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Re: A Miscellaneous Problem that I can't work out!
And here's a plot
Last edited by krassi_holmz (2006-01-06 07:33:24)
IPBLE: Increasing Performance By Lowering Expectations.