No you didnt got my problem ,I know that  I am solving for y^2,and after solving for y^2 I have to remove the square,The problem is different just solve it and I will tell it about...
Actually I am solving for this

Ok before you guys think too much let me tell you where I got this from...as I said its about square root fo a complex number
Let z be a complex number

and its square root be c

Then

So

--- Eq1

--- Eq 2

Now every where they (in books,resource,etc)  find x using quadratic formula, and after that they substitute x in Eq2 to find y.But what I am doing is I am trying to find y using quadratic formula ,but my signs(+/-) doesn’t matches. I think its math and what process we take it doesn’t matters ,the answer will be always same. I must be doing something very very silly...which is not coming into my mind right now but it will come later it always happens with me.

anonimnystefy yes what you got I also got that using that equation,but things changes when I use

The correct answer will be

And thanks for reply

Last edited by debjit625 (2012-07-30 18:58:11)

anonimnystefy  wrote:

That is my solution with the plus/minus sign inside the root taken as +. I am sure taking the minus sign would work as well.

No the minus will not work in this case , as we are finding y^2 and y^2 cant be negative.
But thats not the big problem of mine...my problem is that I can't get to the answer using this equation

And the correct answer for x and y in my book and every where else is

Another thing I want to say,when I write the equation

to this,i.e.. moving the equation from one side to another

I get correct answer.Is here I am doing something wrong?

Last edited by debjit625 (2012-07-30 19:27:52)

Ok ,I was going to ask to you to show the steps but suddenly I realized that I have got it...
Actually I answered my question in post #9

Thanks for your time bro, "talking to you made my crazy mind to work"