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#1 2012-07-01 13:42:56

rajinikanth0602
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a challenging problem for all

(1/x)+(1.3/xsqr)+(1.3.5/xcube)+.........

#2 2012-07-01 14:56:43

Agnishom
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Re: a challenging problem for all

Rajnikanth will always challenge
Bharat mahan hain kiun ki ish desh me Rajnikanth hai


'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'
'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
'Who are you to judge everything?' -Alokananda

#3 2012-07-01 17:08:48

bobbym
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Re: a challenging problem for all

Hi rajinikanth0602;

Welcome to the forum. I have latexed what I think your question is:


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#4 2012-07-02 23:59:46

rajinikanth0602
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Re: a challenging problem for all

i will challenge that i will give 7000 rupees for solving dis problem or any important information about that sequence or range of that sequence

Last edited by rajinikanth0602 (2012-07-03 00:02:26)

#5 2012-07-03 02:07:06

bobbym
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Re: a challenging problem for all

Hi rajinikanth0602;

Save the rupees but that sum diverges.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#6 2012-07-03 02:56:31

anonimnystefy
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Re: a challenging problem for all

Hi bobbym

Is it possible to get a GF of it? I think I have something, but now I am even more unsure of it.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#7 2012-07-03 03:02:44

bobbym
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Re: a challenging problem for all

Hi;

I do not know the answer to that. What I do know is that I have seen that sum before. It is an asymptotic sum. They usually diverge, this one is no different.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#8 2012-07-05 01:55:07

rajinikanth0602
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Re: a challenging problem for all

plz bobby sir give any information about it

#9 2012-07-05 02:08:37

bobbym
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Re: a challenging problem for all

Hi rajinikanth0602;

You can call me bobbym here. That is close to my name.

At present, all I know is that it diverges. I do not have anything else. If I get something I will definitely post it for you.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#10 2012-07-23 00:51:54

rajinikanth0602
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Re: a challenging problem for all

thank u for ur wonder full replies and i had never saw the sites like this that will take care of every ones problems

#11 2012-07-23 01:23:13

bobbym
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Re: a challenging problem for all

Hi rajinikanth0602;

I guess I should say you are welcome but I have not solved the problem yet.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#12 2012-07-23 01:27:23

rajinikanth0602
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Re: a challenging problem for all

watz ur job sir

#13 2012-07-23 01:30:25

bobbym
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Re: a challenging problem for all

Hi;

Currently I am retired.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#14 2012-07-23 01:31:36

rajinikanth0602
Member

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Re: a challenging problem for all

watz ur job sir and say any info about you and frm which country

Last edited by rajinikanth0602 (2012-07-23 01:37:12)

#15 2012-07-23 01:38:59

bobbym
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Re: a challenging problem for all

Hi rajinikanth0602;

As I have said, I am retired due to injuries. That means I no longer work.

When I did work my jobs were math related primarily in numerical analysis, combinatorics, probability and programming mainly.

I am from the United States. I am of southern extraction.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#16 2012-07-23 01:40:13

rajinikanth0602
Member

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Re: a challenging problem for all

can u give ur email id im frm india

Last edited by rajinikanth0602 (2012-07-23 01:41:09)

#17 2012-07-23 01:43:47

bobbym
Administrator

Online

Re: a challenging problem for all

Hi rajinikanth0602;

I am sorry but that I can not do on the forum.

Can I ask what you need?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#18 2012-07-23 01:50:42

bobbym
Administrator

Online

Re: a challenging problem for all

Hi rajinikanth0602;

I will do what I can but we can only work through the forum. You can post any problem or most anything right in here. You will receive help and not always from me. There are capable people here.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#19 2012-07-23 02:11:43

anonimnystefy
Real Member

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Re: a challenging problem for all

Hi

See if you can use this:


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#20 2012-07-23 02:21:21

bobbym
Administrator

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Re: a challenging problem for all

Hi;

It is questionable that you will be able to move the y^2 through the Sigma like that. Or maybe you can. What do you get for an answer?

It seems simplest to me to just prove that the numerator of the summand is larger than the denominator. Then you would be adding an infinite number of terms all greater than 1. Terms that are never getting smaller. This looks like it can be done by induction.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#21 2012-07-23 03:01:55

anonimnystefy
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Re: a challenging problem for all

Hi bobbym

S(sqrt(x)) is the same as the sum above. I just want a closed form. Like 1/(1-x) is the EGF for:



even though the sequence doesn't converge.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#22 2012-07-23 03:08:09

bobbym
Administrator

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Re: a challenging problem for all

How can you get a closed form? The upper index of summation is not a variable. Either it sums to some constant or it diverges.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#23 2012-07-23 03:10:29

anonimnystefy
Real Member

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Re: a challenging problem for all

Upper index of summation?


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

#24 2012-07-23 03:28:03

bobbym
Administrator

Online

Re: a challenging problem for all


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

#25 2012-07-23 03:40:41

anonimnystefy
Real Member

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Re: a challenging problem for all

What about it?


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment

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