Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #301 20120715 04:30:23
Re: PSLQ and LLL?I am quoting here for the sake of easier access tome.
I will now do the next lines. Then we will have to find a Lattice Reduce function for Maxima. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #302 20120715 04:33:06
Re: PSLQ and LLL?Okay, work on them, I have to do a chore be back soon. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #303 20120715 04:37:08
Re: PSLQ and LLL?What does the Rationalize do, again? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #304 20120715 06:15:41
Re: PSLQ and LLL?Turns a decimal into the closest fraction. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #305 20120715 06:28:02
Re: PSLQ and LLL?I figured that out and tried writing a Maxima function, but it is not working: Code:ratnum(a,dig) := round(float(a)*(10^dig))/10^dig; The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #306 20120715 06:32:54
Re: PSLQ and LLL?I thought maxima had a similar command. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #307 20120715 06:42:11
Re: PSLQ and LLL?It doesn't. Or at least I don't know about it. My function returns good number for rationals but not reals. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #308 20120715 06:45:07
Re: PSLQ and LLL?Hold on, I am installing the newest Geogebra. I will see what I can find. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #309 20120715 06:54:07
Re: PSLQ and LLL?But what about a real number? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #310 20120715 06:54:25#311 20120715 06:56:40
Re: PSLQ and LLL?e for example. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #312 20120715 06:57:49#313 20120715 06:58:21
Re: PSLQ and LLL?That is not e. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #314 20120715 06:59:41#315 20120715 07:02:38
Re: PSLQ and LLL?Why does your function have another parameter? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #316 20120715 07:04:18
Re: PSLQ and LLL?One thing at a time. We need to stop right here. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #317 20120715 07:05:45
Re: PSLQ and LLL?Last edited by anonimnystefy (20120715 07:05:59) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #318 20120715 07:13:16
Re: PSLQ and LLL?Nope! That little symbol has an infinite amount of digits. It represents a transcendental number. What does that mean? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #319 20120715 07:14:43
Re: PSLQ and LLL?It is not a root of an equation with rational coefficients? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #320 20120715 07:18:14
Re: PSLQ and LLL?No, not exactly what we need here. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #321 20120715 08:28:00
Re: PSLQ and LLL?Ok, what next? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #322 20120715 08:39:31
Re: PSLQ and LLL?I gave you the Rationalize command. So what is next? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #323 20120715 10:15:35
Re: PSLQ and LLL?Arghh, the troubling Lattice Reduce. We will need to find a way to do it in Maxima. Is there a code for tthe Lattice Reduce function? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #324 20120715 11:54:04
Re: PSLQ and LLL?Is the rest of the program done? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #325 20120715 12:08:48
Re: PSLQ and LLL?No. Only up to the Lattice Reduce. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment 