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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Hello mathematicians.

I'm back: D

I wanted to know if they know how to make similar triangles without drawing parallels to the sides of the triangle.

"... And as we let our own light shine, we unconsciously give other people permission to do the same. As we're liberated from our own fear, our presence automatically liberates others."

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,380

hi mathmatiKs

To be similar, the angles must be the same or one triangle must be an exact enlargement of the other.

The parallel lines method works because it maintains the same angles.

You could try extending each side and doubling the lengths. (or substitute any other scale factor, eg trebling)

You could draw a line perpendicular to each side. The triangle these make would also be similar. (diagram below)

You could extend this idea to making the three new lines at any fixed angle to the original sides.

I could go on .........

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Thanks Bob Bundy

Asked because I found a method to draw three triangles similar to an extent that they have a special relationship within the interior angles of the first triangle.

How sould upload a picture to show you an example?

"... And as we let our own light shine, we unconsciously give other people permission to do the same. As we're liberated from our own fear, our presence automatically liberates others."

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,380

hi mathmatiKs

I'm assuming you have the picture on your computer.

(1) make sure you click **Post Reply** not **Quick reply**

Your picture should not be too large ( < 100Kb)

(2) Click Image Upload

(3) and browse to your picture

(4) click submit.

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

This is what I was saying.

.... 500 kb

yeahh

I do not see the picture I uploaded.

*Last edited by mathmatiKs (2012-07-09 16:53:15)*

"... And as we let our own light shine, we unconsciously give other people permission to do the same. As we're liberated from our own fear, our presence automatically liberates others."

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,380

hi mathmatiKs

500 Kb is too large. If you try to upload it doesn't appear. That happened to me for the shot in post 4.

I'm using Windows 7 so I used Paint to reduce it in size. That's why the shot is poor resolution.

For diagrams I use GIF format. That takes a lot less space than the same in JPG.

Or maybe you can store it on-line somewhere and point to it using

[img]web address of picture[/img]

If all else fails you could write a written description such as:

Draw a line AB. At A, mark a 30 degree angle and draw the line AC so that CAB = 30. Drop a perpendicular from C to B. etc etc.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Hi mathmatiKs

You can store the pics on mediafire then link to there from here.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Hi Bob bundy.

I was down to 100kb but nothing happened.

Thanks anonimnystefy

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Hi Bob Bundy

Tell the process to draw the triangles would be very long, since it does not write well in English (I'm using a little tradutor)

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Hello mathematicians.

I found an easier way of construction of similar triangles.

I'm still seeing in relation to the building or if the relationship is either.

Here's the procedure:

1) Draw the triangle ABC.

2) Taking the measure of segment AB and draw a circle in C

3) Taking the measure of segment BC and draw a circle at

4) Taking the measure of segento CA and draw a circle in B

5) After this, you are 3 circles with 9 points of intersection. Joining of three points, the right way, you are 3 similar triangles.

Oh, and something else. I have to prove but I can use what I had found earlier for construction of similar triangles. For now I let them try and see how fun and crazy it is drawing similar triangles using ruler, pencil and compass.

I hope they serve to help or interest to them.

(Excuse me for mistakes but I use a translator )

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

Hi mathmatiKs;

Sounds like geogebra is what you need.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Hi Bobbym.

I am currently using Kig, which in my opinion is better.

Try it.

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Testing ...

Do I have to wait to upload an image that is completely or just subis you can post?

*Last edited by mathmatiKs (2012-08-04 08:20:46)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

I am getting for the drawing:

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

(((The triangles are similar: ENG NFM GMH ))) no valid

Ups!

The construction is not correct!

*Last edited by mathmatiKs (2012-08-04 08:27:07)*

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Measure the segment AB and draw a circle at center C

Measure the AC segment and draw a circle in center B

Measure the segment CB and draw a circle in center A

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

Testing ...

Do I have to wait to upload an image that is completely or just subis you can post?

Use the Upload Slots.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

bob bundy wrote:

hi mathmatiKs

I'm assuming you have the picture on your computer.

(1) make sure you click

Post ReplynotQuick replyYour picture should not be too large ( < 100Kb)

(2) Click Image Upload

(3) and browse to your picture

(4) click submit.

I use this.

What browser do I have to use?

Firefox Mozzilla

Google Chrome

Etc..

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

I use Firefox.

This is my new drawing I do not think it is correct.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

This well done. I could put names to the points?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

Okay, I will label the points now. They are slightly out of position because I did them manually.

How are you coming with your upload?

Why are you not using 2 intersecting lines to create as many similar triangles as you need?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**mathmatiKs****Member**- Registered: 2012-04-14
- Posts: 45

Wait for me a little hard to see more or less.

Since I have not yet found an easy way to pull it.

Waiting For

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,380

hi mathmatiKs

I have drawn triangle ABC.

Measured AB and made circle centre C with radius CD so that CD = AB

Measured AC and made circle centre B with radius BE so that BE = AC

Measured BC and made circle centre A with radius AF so that AF = BC (slightly inaccurate as the point is hard to place exactly)

This gives first diagram. The circles only cross in 6 points.

I made any three circles for my second diagram and there are always a maximum of 6 points!

???

Bob

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,365

Hi;

Can you see my drawing?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

**Online**

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,380

Yes. You also have 6 points. (I typed 8 points in error but have edited it. I have trouble counting to 8 !! )

Bob

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