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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Wow,they totally missed it!

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Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,569

Missed what?

I will post another problem in here.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

They missed your post.

I am looking forward to the problem.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

When can I expect the problem?

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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**A game is played. You roll a red die and then roll as many green die as the number on the red die. What is the probability of the sum of the green die equalling 17?**

**Is this a generating function problem?**

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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My first guess would be a no,but I will have to look at it a little.

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**anonimnystefy****Real Member**- From: The Foundation
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Maybe the coeff of x**17 in ((x+x**2+x**3+x**4+x**5+x**6)+ (x+x**2+x**3+x**4+x**5+x**6)**2+(x+x**2+x**3+x**4+x**5+x**6)**3+ (x+x**2+x**3+x**4+x**5+x**6)**4+(x+x**2+x**3+x**4+x**5+x**6)**5+ (x+x**2+x**3+x**4+x**5+x**6)**6)/6?

*Last edited by anonimnystefy (2012-05-03 05:22:15)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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That is almost correct except there is an error. Do you see it?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Oh,yeah,I wasn't really sure about that division by six. Thinking about it again it seems logical not to include it.

*Last edited by anonimnystefy (2012-05-03 05:30:40)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Without that 6 down there we would have a combinatorics problem but this is a probability problem.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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Well,I need to divide by what we get when we sub x=1.

*Last edited by anonimnystefy (2012-05-03 05:34:09)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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But as it stands with or without that 6 the answer is not correct.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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Is the GF okay?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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We have not even established the need for one but that one is not right.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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Why is it not correct?

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**bobbym****Administrator**- From: Bumpkinland
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It needs some work done on it.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Anything besides mulirplying by a constant?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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I would think that multiplying by any constant would not fix it. But that is another question.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Couod you tell me where the problem is?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,569

Do you have access to a CAS right now?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Not right now. Phone.

Maybe I could try getting on my laptop,but that doesn't seem probable. At least not till 10.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Remember any answer is not any good unless it is arrived at in two different ways. Two different directions, then you have some certainty.

I know of a forum filled with olympiad hopefuls. They try to solve combinatoric problems. They post the wrong answer, why? Because they did not check it to see if it was possibly correct. Computers and combinatorics are married. When you use them together you will be more accurate than those who do not.

I think if you would have expanded that gf you would have seen that it can not be right. We would not be going back and forth right now. In short, we would be going faster.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

I just had an idea! Should those be EGFs instead of OGFs?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Does order count? Is 5 + 3 + 2 different than 3 + 5 + 2?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,522

Nope. Isn't that why it should be an EGF?

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