Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #2 20051227 12:24:08
Re: derivative of an exponential functionYou need the product rule: f'(uv) = f(u)f'(v) + f'(u)f(v) Why did the vector cross the road? It wanted to be normal. #4 20051227 17:31:22
Re: derivative of an exponential functionx^4*3^x(5+x*ln 3)=x^4*3^x*x(5/x+ln3)=x^5*3^x*(5/x+ln3) IPBLE: Increasing Performance By Lowering Expectations. #7 20051227 18:30:47
Re: derivative of an exponential functionI'm not sure I've done differentiation of the form u^x yet. I think I know how to do it but I'm not sure so I'll let someone who knows tell you. Last edited by mikau (20051227 18:35:14) A logarithm is just a misspelled algorithm. #8 20051227 18:43:12
Re: derivative of an exponential functionit's not that difficult really. just apply log to both sides and differentiate. #9 20051228 01:12:18
Re: derivative of an exponential functiond/dx (a^x) = a^x * ln(a) "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #12 20051229 12:40:52
Re: derivative of an exponential functionhristo, where are you from? IPBLE: Increasing Performance By Lowering Expectations. #14 20051230 04:19:00
Re: derivative of an exponential functionYes. And i'm asking because his name is like someone from East Europe. IPBLE: Increasing Performance By Lowering Expectations. 