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You are not logged in. #1 20120411 04:51:53
PSLQ and LLL?Hi guys Last edited by anonimnystefy (20120411 04:52:55) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #2 20120411 05:43:59
Re: PSLQ and LLL?Hi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #3 20120411 05:45:51
Re: PSLQ and LLL?Hi bobbym The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #4 20120411 05:53:36
Re: PSLQ and LLL?To demonstrate it requires a computer. It is not a hand method. I already have a whole thread on this in the computer math thread. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #5 20120411 05:55:27
Re: PSLQ and LLL?If you mean the one where you showed this to gAr,then I saw that one,but couldn't get any of it. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #6 20120411 06:07:55
Re: PSLQ and LLL?That is your input vector. The first element is the number you wish to find an integer relation for in terms of the others. You do the first run with 15 digits of precision. You get: Then you do another run with 25 digits of precision ( commion move in numerical analysis ), you get: The top row has the smallest coefficients and is the answer. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #7 20120411 06:08:49
Re: PSLQ and LLL?That is your input vector. The first element is the number you wish to find an integer relation for in terms of the others. You do the first run with 15 digits of precision. You get: Then you do another run with 25 digits of precision ( common move in numerical analysis ), you get: The top row has the smallest coefficients and is the answer. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #8 20120411 06:15:01
Re: PSLQ and LLL?hi bobbym Last edited by anonimnystefy (20120411 06:16:07) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #9 20120411 06:18:02
Re: PSLQ and LLL?Hi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #10 20120411 06:18:54
Re: PSLQ and LLL?That is the same,but why is there 1 in the first row vector? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #11 20120411 06:22:27
Re: PSLQ and LLL?Everything in the vector after the first is a number that we are trying to fit that constant on the left with. I will demonstrate with another toy example. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #12 20120411 06:25:00
Re: PSLQ and LLL?Hi bobbym Last edited by anonimnystefy (20120411 06:29:00) The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #13 20120411 06:28:44
Re: PSLQ and LLL?That's is correct. One of its answers will be x = 2 and y = 3. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #14 20120411 06:30:58
Re: PSLQ and LLL?I don't understand many things I use,but I always try to understand at least a bit.But I wont insist on it. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #15 20120411 06:33:01
Re: PSLQ and LLL?I use it in mathematica, maple has a better one built in. Sage has a good one. I do not know about maxima. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #16 20120411 06:35:10
Re: PSLQ and LLL?I know you wrote your own code,but how can I program in Maxima? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #18 20120411 06:38:38
Re: PSLQ and LLL?Yes I do. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #19 20120411 06:40:43
Re: PSLQ and LLL?Do you know how to program in it? In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #20 20120411 06:44:11
Re: PSLQ and LLL?No,I need help.First of all there are two programs that use maxima on my desktop.One is wxMaxima and the other one is XMaxima.Which one should I write the code in? The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #21 20120411 06:46:00
Re: PSLQ and LLL?I have no idea. I have not used the standalone maxima for many years and do not remember. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #22 20120411 06:54:32
Re: PSLQ and LLL?Could you check out somewhere,because I am clueless. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #24 20120411 06:55:59
Re: PSLQ and LLL?Ok.I will be back in around half an hour,maybe less. The limit operator is just an excuse for doing something you know you can't. “It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman “Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment #25 20120411 07:09:21
Re: PSLQ and LLL?I will take a break and get some air. In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. 