I'm new to sigma notation and I'm supposed to put 3 + 6+ 12+ 24 + 48 in it, but I really can't figure out how to do it. I've tried for so long, but nothing I try works. Can come help?
n <- end of the sequence
k = 1 <- starting
Last edited by MajikWaffle (2005-12-14 17:57:43)
I know all that, it's just this problem I can't get.
Don't ask me how I got this, I couldn't tell you. Just a bunch of guessing and checking:
Summation of k = 1 to n of 2^(k+1) - 2^(k-1)
Last edited by Ricky (2005-12-14 18:11:14)
I couldn't get that to work out. Are you sure?
2^(k+1) - 2^(k-1)
K = 1:
2^2 - 2^0 = 4 - 1 = 3
K = 2:
2^3 - 2^1 = 8 - 2 = 6
K = 3:
2^4 - 2^2 = 16 - 4 = 12
K = 4:
2^5 - 2^3 = 32 - 8 = 24
And so on.
Last edited by Ricky (2005-12-14 18:17:51)
Is this it?
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
I think this one is cleaner:
El que pega primero pega dos veces.
ryos, what's n?
And where can I look up commands for this code?