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You are not logged in. #1 20051215 05:51:22
Finding an inverse functionHey, Student: "What's a corollary?" Lecturer: "What's a corollary? It's like when a theorem has a child. And names it corollary." #2 20051215 06:14:38
Re: Finding an inverse functionIt's got me stumped too. I've never seen a problem involving finding the inverse that needed differentiation before, and I don't think this one's any different. It's just quite hard. I'll try it again later, because it's annoying me with its unsolvedness. Why did the vector cross the road? It wanted to be normal. #4 20051215 07:30:48
Re: Finding an inverse functionS(x+L) is S*(x+L) and not a function, right? Using y as f(x) (as it's easier): Last edited by Ricky (20051215 07:31:16) "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #6 20051221 15:37:33
Re: Finding an inverse functionRicky, I thought you have to set y=0 for quadratic equation. Please explain. Last edited by John E. Franklin (20051221 15:44:21) igloo myrtilles fourmis #7 20051222 02:32:50
Re: Finding an inverse functionIf you draw the line y = x, the inverse of a function should be mirrored across that line. That is, f(x,y) = f¹(y,x)
y isn't the variable. x is: "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #8 20051222 10:13:40
Re: Finding an inverse functionx and y are variables, so I don't think you can set y equal to a. igloo myrtilles fourmis #9 20051222 13:03:40
Re: Finding an inverse functionVariable or constant, it doesn't matter, a is just a "label" for y. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." 