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#101 2012-03-13 21:45:00

bobbym
Administrator

Online

Re: Interesting transformations on graphs!!!

For one thing it could already be known. I am not an expert on Graph theory.


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#102 2012-03-13 21:49:56

anonimnystefy
Real Member

Offline

Re: Interesting transformations on graphs!!!

hi bobbym

maybe it is.but let's pretend it isn't and build up on it.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#103 2012-03-13 21:55:35

bobbym
Administrator

Online

Re: Interesting transformations on graphs!!!

What does it mean to add to graphs here?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#104 2012-03-13 21:58:56

anonimnystefy
Real Member

Offline

Re: Interesting transformations on graphs!!!

hi bobbym

it means just to add their polynomials to get a third polynomial and then draw a graph that is represented by that polynomial.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#105 2012-03-13 22:06:31

bobbym
Administrator

Online

Re: Interesting transformations on graphs!!!

Yes, I know but what did that do? Why would we add them in the first place?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

#106 2012-03-13 22:16:00

anonimnystefy
Real Member

Offline

Re: Interesting transformations on graphs!!!

hi bobbym

maybe we should ask the inverse question.now that we have added the graphs what have we achieved and what purpose does this serve?

anyway,what interests me more than adding graphs is multiplying them.and i suspect that these two binary operations have something to do with drawability as well,but that's just a guess.


The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“Taking a new step, uttering a new word, is what people fear most.” ― Fyodor Dostoyevsky, Crime and Punishment
 

#107 2012-03-14 01:16:53

bobbym
Administrator

Online

Re: Interesting transformations on graphs!!!

Okay, when you multiply the graph what does that mean?


In mathematics, you don't understand things. You just get used to them.
I have the result, but I do not yet know how to get it.
All physicists, and a good many quite respectable mathematicians are contemptuous about proof.
 

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