You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**Fruityloop****Member**- Registered: 2009-05-18
- Posts: 135

Hello everybody! I haven't posted in a long time. But anyways...

I was working on this problem called 'The fighting fishes of Siam' by the late, great, Sam Loyd and it states that

there are two kinds of fishes, king fish and devil fish. They inevitably attack each other on sight. Three devil fish

counterbalance one king fish. Four devil fish can kill a king fish in 3 minutes with each additional fish making the new group

proportionately quicker. So I did the following... 4*3 = 12, 5*x=12, so x=2.4 or 144 seconds for 5 fish.

But the solution in the back of the book says that each fish added to a group of x fish reduces the time taken by 1/x. So for five fish they say it will take 135 seconds. The time is reduced by 1/4. This seems reasonable, but what if one devil fish killed a king fish in 3 minutes with each additional fish making the new group proportionately quicker? Then two fish would take no time at all! What about three fish then? What's going on?

**The eclipses from Algol come further apart in time when the Earth is moving away from Algol and closer together in time when the Earth is moving towards Algol, thereby proving that the speed of light is variable and that Einstein's Special Theory of Relativity is wrong.**

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 105,666

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

Offline

Pages: **1**