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You are not logged in. #1 20051207 04:05:26
Calculating probability of a condorcet paradoxIn this problem there are 3 voters listing their preferences over 3 political parties x,y,z. Using majority rule, the condorcet paradox occurs when, for example, x > y, y > z, z > x . This creates a cycle and no one wins the abstract election. #2 20051207 09:58:50
Re: Calculating probability of a condorcet paradoxI don't think I understand the question. What I think you are looking for is if the matrix formed is reflexive, I can't find a case where it's not. If they all have to have different ordering, i.e.: Last edited by Ricky (20051207 10:13:20) "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #3 20051207 16:38:58
Re: Calculating probability of a condorcet paradoxThis is new to me, but looks interesting. "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #4 20051208 01:42:37
Re: Calculating probability of a condorcet paradox
No, it does not matter whether you count the third voters preferences before the second. However, if voter 2 had voter 3's preferences and voter 3 had voter 2's preferences it would be a different outcome. #5 20051208 07:35:46
Re: Calculating probability of a condorcet paradoxSure? (Apart from you not rearranging them, but I know what you mean) "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #6 20051209 02:07:04
Re: Calculating probability of a condorcet paradox
So tell me how to do it? Please? #7 20051209 21:51:31
Re: Calculating probability of a condorcet paradoxI have been thinking about this off and on, so I am just going to write down my thoughts. "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman 