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#1 2005-12-01 23:44:39

Vega
Guest

a bit difficult problem ...

Hey, got a problem here, can anyone solve this?

if 364VFA7XLT = 14210576
if 364VFA7XRR = 33760049
if 364VFA83FQ = 29200854
if 364VEY0T5D = 30612263
if 364VEYJ4MY = 87185950
if 364VEYC5PC = 36404338
if 364veyjwzy = 05932419
if 364veyN29T = 61341839
if 364veyL3FF = 36919718
if 364veyL38M = 02719321
if 364veyBXPX = 95248825
if 364veyBVKD = 43763843
if 364veyBY7W = 25581380
if 364veyJMCW = 43611219
if 364veyBVFG = 30820078
if 364veyBWCN = 98442780
if 364VEYBTP5 = 85539457
if 364VEYH8WT = 13208822
if 364VEYH73J = 05063395
if 364VEYCTSJ = 43636183
if 364VEY9YLH = 22989241

Then what does 364VEQGKZP equal?

please let me know smile

#2 2005-12-02 03:38:19

yttrium88
Member
Registered: 2005-12-01
Posts: 20

Re: a bit difficult problem ...

Hmm...

I would almost just write off the initial '364' as having no control over the value of the string, but then again, all the resulting numbers have 8 digits.

Is the some way you could check what the numeric values of other strings is?

Where did this problem come from?

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#3 2005-12-02 03:45:19

ryos
Member
Registered: 2005-08-04
Posts: 394

Re: a bit difficult problem ...

My second thought is that it's using some sort of weird base system and representing it with letters. That's definitely not my forte, though.


El que pega primero pega dos veces.

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#4 2005-12-02 07:31:05

Vega
Guest

Re: a bit difficult problem ...

It's for a nextel phone ... there should be a mathematical solution for this hmm

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