Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

#1 2005-11-29 04:18:02

RickyOswaldIOW
Full Member

Offline

More factorising revision

Factorising quadratics that is;

I have y = 2 - 3x - 2x^2.

Normally I would take out the coefficient of x^2 and thus have;

y = -2[x^2 + 1(1/2) - 1]

But I can't seem to factorise this?...


Aloha Nui means Goodbye.

#2 2005-11-29 04:21:53

RickyOswaldIOW
Full Member

Offline

Re: More factorising revision

Okay, maybe I should not take the 2 from the x^2 and instead have;

-[2x^2 + 3x - 2].

I think this will work but I have to go out now, thanks anyway smile


Aloha Nui means Goodbye.

#3 2005-11-29 05:08:15

mathsyperson
Moderator

Offline

Re: More factorising revision

That would work. -[2x² + 3x - 2] factorises to give -(x+2)(2x-1).


Why did the vector cross the road?
It wanted to be normal.

Board footer

Powered by FluxBB