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You are not logged in. #1 20051122 14:32:54
Antiderivative problem...should be pretty easyA stone is thrown straight down from the edge of a roof, 1050 feet above the ground, at a speed of 5 feet per second. #2 20051122 15:21:53
Re: Antiderivative problem...should be pretty easyS = ut + at²/2, u=0 Character is who you are when no one is looking. #3 20051122 15:35:07
Re: Antiderivative problem...should be pretty easyThanks, I got the answer though. #4 20051123 04:22:07
Re: Antiderivative problem...should be pretty easyI think ganesh forgot about the '/2' bit in his formula, so got the distance travelled in A double what it should have been, and that error carried forward into B. Why did the vector cross the road? It wanted to be normal. #5 20051125 02:15:26
Re: Antiderivative problem...should be pretty easy623.097 ft @ 5s #6 20051125 02:16:37
Re: Antiderivative problem...should be pretty easyActually, Ganesh forgot about the initial velocity that the stone was thrown. #7 20051125 03:54:02
Re: Antiderivative problem...should be pretty easyOoh, ganesh missed the initial velocity as well. He even said 'u=0'. He must have been having an off day. Why did the vector cross the road? It wanted to be normal. #8 20051125 04:23:30
Re: Antiderivative problem...should be pretty easyMathyperson, #9 20051125 07:45:46
Re: Antiderivative problem...should be pretty easyHi irspow. Good posts. Would you like to become a Member? "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman #10 20051126 05:34:19
Re: Antiderivative problem...should be pretty easy1 inch stone reaches terminal velocity at about 23.93m/s (m=18.9g) 