Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**DaveRobinsonUK****Member**- Registered: 2010-04-24
- Posts: 123

Hi All

I have been doing o.k with this stuff so far, but have hit a block with one of them.

here it is.

if I do

andi can't get the required

fromi suppose what I am asking is how do I split this up into two functions.

Cheers

Dave

Can feel it coming together.. Slowly but Surely

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi Dave;

Why do you need to use the chain rule?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

**gAr****Member**- Registered: 2011-01-09
- Posts: 3,479

Hi all,

Dave, The chain rule is

"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

I suggest memorizing this one. For the next time.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

**DaveRobinsonUK****Member**- Registered: 2010-04-24
- Posts: 123

Hi huys

I'm just following this book I have and the questions are supposed to get you

used to using and understanding the idea. Up until this one they pretty much

the same. Some log, some trig some simple composite functions.

in the book it says the chain rule is

this works fine for

The problem is I don't know how to handle to 6x^2 term, in terms a composite function.

if i make

andi then make

it is on

where I get stuck.Can feel it coming together.. Slowly but Surely

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi Dave;

Can you finish now?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

**gAr****Member**- Registered: 2011-01-09
- Posts: 3,479

Hi dave,

From the equation:

"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

Offline

**bob bundy****Administrator**- Registered: 2010-06-20
- Posts: 8,206

hi Dave,

I've been away so I've only just read this thread.

This is what I think is causing you difficulty.

Some functions can be differentiated using the basic rule

eg.

Then some functions will be simple functions added or subtracted.

For these you may differentiate each bit and then add or subtract the results.

eg.

Then you have the ones where the chain rule applies.

y is a function of say u, where u is a function of x. That's when you have to use

eg.

(There's also the product and quotient rules but I'll skip over these for now, in case you haven't done these yet.)

Once you've got the basics of each process the exercises start to get harder by muddling up bits of one method with bits of another.

In

you have a chain rule **and** a sum, with the second bit just a simple differentiation.

You're meant to spot that the first bit needs the chain rule

and the second bit can be just differentiated using the 'multiply by the power and drop the power by one' rule.

So you only need the chain rule for the first half of the function. I've done that above as an example.

And I've also done the second bit in an example above. So just add the two results together.

I've added a little diagram to show when the chain rule is needed. When you meet the product and quotient rules I've got diagrams for them too. That should help you to decide which rule to apply when.

Bob

*Last edited by bob bundy (2011-08-07 06:59:47)*

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**DaveRobinsonUK****Member**- Registered: 2010-04-24
- Posts: 123

Hi All

I think I get it now. So in this one the chain rule is only supposed to be used on the

first e term and then the

the end.

Something like this.

This book never even mentioned anything of the sort. Though I suppose it is meant

for tutored lessons.

Can feel it coming together.. Slowly but Surely

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

That is what I meant in my first post. The 6x^2 is a power rule and even the exponential term can be done by a rule. But if you you are forced to use the chain rule you would only use it on the e^(3x).

Differentiation is a linear operator meaning that you apply it term by term.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

**DaveRobinsonUK****Member**- Registered: 2010-04-24
- Posts: 123

Hi Bobby

Thanks for that.

Yes I understand now. Just worked the rest of the remaining problems on the exercise

and got them all.

More reading needed though.

Can feel it coming together.. Slowly but Surely

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi Dave;

Glad to hear you got them right, Post any you get problems on.

How are you doing, I have not heard from you in a while?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

**DaveRobinsonUK****Member**- Registered: 2010-04-24
- Posts: 123

Yes I am good. Supposed to be starting work this week, the place

called last week to say they were moving all their kit over to a new

office and then getting me in after that. All excited

Other than that just been going over things I have forgotten and trying

to get MATLAB to do fractals. This has of course meant brushing up on

complex numbers and infinite series.

I sort of understand how it works, but not enough to get it to work inside

MATLAB.

Maybe I should start a new post on that?

Can feel it coming together.. Slowly but Surely

Offline

**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi DaveRobinsonUK;

Good luck with the new job! You will do fine.

Matlab, unfortunately that is one I do not use.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

Offline

Pages: **1**