Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

#1 2005-11-20 04:06:03

Sarah
Guest

equations

Hello there,

I really need your help sad

the lines px + 4y - 2 = 0 and 2x - y + p = 0 are perpendicular. Find the value of p.


The lines x+2y+12=0, x-2y+3=0, 2y+x-8=0 and x-2y-2=0 form a quadrilateral. What is the best description for this quadrilateral?


I really feel stupid :-|

thank you so muchhh!!!

#2 2005-11-20 04:40:53

austin81
Member

Offline

Re: equations

Two lines are perpendicular if the product of their gradients equals -1
Write each equation in the form y=mx+c:
where m is the gradient.
px+4y-2=0
y=-(p/4)x+1/2......., m1=-p/4
2x-y+p=0
y=2x+p.........., m2=2
m1*m2=-1...., (-p/4)*2=-1....p=2

Board footer

Powered by FluxBB