Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**anandbrar****Member**- Registered: 2011-07-20
- Posts: 70

An egg-seller was on his way to a village. On his way, a fool collided with him and all his eggs broke. They both went to the village head-man. When the head-man asked how many eggs he had, the egg-seller told him,

"When counted in twos, 1 remains,

When counted in threes, 2 remain,

When counted in fours, 3 remain,

When counted in fives, 4 remain,

When counted in sixes, 5 remain,

When counted in sevens, none remain...

I had less than 150 eggs."

How many eggs did he have?

*Last edited by anandbrar (2011-07-21 06:39:49)*

"widen your gaze... extend beyond the obvious..."

Offline

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,311

hi anandbrar

I got

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Offline

**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,392

hi anandbar

yup i did this problem except it wasn't bout eggs.

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

Offline

**anandbrar****Member**- Registered: 2011-07-20
- Posts: 70

hi bob bundy, anonimnystefy

Both your ans are correct.

"widen your gaze... extend beyond the obvious..."

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,574

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**anandbrar****Member**- Registered: 2011-07-20
- Posts: 70

hi bobbym,

why did you multiply with 3*3*...?

"widen your gaze... extend beyond the obvious..."

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,574

Hi;

Each mutiplication does not effect the solution set. But you multiply until the number is congruent to 1 for the modulo. This has the effect of solving for the variable.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**anandbrar****Member**- Registered: 2011-07-20
- Posts: 70

Hi, I had a query..

If he were to say:

"When counted in twos, 1 remains,

When counted in threes, 2 remain,

When counted in fours, 3 remain,

When counted in fives, 4 remain,

When counted in sixes, 5 remain,

When counted in sevens, 6 remain,...

so on till

When counted in elevens, none remain"

Will the least answer be 30239?

Could anyone verify if this would be the least answer...thanks..

"widen your gaze... extend beyond the obvious..."

Offline

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,531

Hi anandbrar,

I think the answer would be 2519.

Character is who you are when no one is looking.

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,574

Hi;

2519 that is what I am getting also.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

Offline

**sandesh234****Member**- Registered: 2011-08-17
- Posts: 7

My answer

Offline

**Muramal****Member**- Registered: 2011-12-17
- Posts: 1

Got it

The question clearly says less than 150 eggs

So why do we have answers by the xxxxxdigits?

It's simply 119 eggs!

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,574

Hi Muramal;

Welcome to the forum. This should clear up the confusion.

Everyone did answer 119 ( see post #2,3 and 5).

The higher number (2519) was for the second problem (post #8) which does not have the <120 restriction.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

Offline

**anna_gg****Member**- Registered: 2012-01-10
- Posts: 113

Suppose we are looking for x, where x is the number of eggs. Then x+1 should be a multiple of 2,3,4,5,6.

The smaller number to meet this criteria is 5x12 = 60, then 120, then 180 etc.

Moreover, x should be a multiple of 7, thus (x+1)mod7 = 1, thus 120-1 = 119, 238 etc.

The number also has to be <150, so it is 119.

Offline

Pages: **1**