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#1 2011-07-18 10:33:52
- Thanh Vân
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Inequality In [1;3]
Let a,b,c be real numbers in [1;3]. prove that
Last edited by Thanh Vân (2011-07-18 10:34:34)
#2 2011-07-18 23:56:17
- anonimnystefy
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Re: Inequality In [1;3]
hi Thanh Vân
i tried to find the maximum value of the left part which is for a=b=c=3 and equals (3√2)/2, and the minimum value of the right part which is for a=b=c=1 and equals (9√2)/2 ,so for any other possible values for a,b and c the inequality will always be true.i think this is not the prefered method for solving this kind of problems but it is the only one i could come up with.
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
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#3 2011-07-20 00:30:31
- Thanh Vân
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Re: Inequality In [1;3]
Hi anonimnystefy.
Look my inequality, you can see Maximun of left Inequality is when a=b=c=3 and minimum right inequality is same as yourself.
But it is very easy to talk so.
I thinks it is a problem very very nice, and we can solve it by basic 's inequality.
Maybe it is CS and AM-GM.
#4 2011-07-22 04:44:29
- gAr
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Re: Inequality In [1;3]
Hi Thanh Vân,
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
#5 2011-07-22 21:14:20
- Thanh Vân
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Re: Inequality In [1;3]
Hi gAr, I don't see you completed solution for my inequality (=left your proven). Please see again your post. Thanks.
#6 2011-07-22 21:25:12
- gAr
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Re: Inequality In [1;3]
Hi Thanh Vân,
Yes, I saw that after posting.
I'll try again sometime later.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."