Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20051109 03:38:53
Cannot freeken get this one!THe puzzle is this: #2 20051109 03:44:31
Re: Cannot freeken get this one!Hmm. In base x, 13 would be x + 3 (we have base 10, so 13 is 10 + 3), which means that your thing would be (x + 3)/2 = 8. Why did the vector cross the road? It wanted to be normal. #3 20051109 04:07:37
Re: Cannot freeken get this one!I understand the basics there in that equation. HOwever, maybe I am just overthinking: #4 20051109 04:12:37
Re: Cannot freeken get this one!No. 10 in base 10 isn't 1. It's 10. Why did the vector cross the road? It wanted to be normal. #5 20051109 04:22:12
Re: Cannot freeken get this one!Ahh, I WAS overthinking it. Missed the equation meaning. #6 20051109 07:31:57
Re: Cannot freeken get this one!LOL! And what a great illustration of bases. "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman 