Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ ¹ ² ³ °
 

You are not logged in. #1 20051104 11:02:06
Differentiation from first principlesI have the equation y = x^3 + 12x  9 #2 20051106 06:55:43
Re: Differentiation from first principlesx = k and x = k+h ????? #3 20051106 08:14:10
Re: Differentiation from first principlesTo differentiate from first principles, you need to consider two points on the curve that are very close to each other. To find the gradient between them, you would divide the difference in y by the difference in x. Why did the vector cross the road? It wanted to be normal. 