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You are not logged in. #1 20050816 20:40:04
0x∞=1 ???Under the topic of linear graphs, we are taught that if two straight lines are perpendicular to each other, then their product of gradients is equal to 1. #2 20050816 20:56:45
Re: 0x∞=1 ???Proof of following "theorem" using vectors method. Last edited by wcy (20050816 20:57:00) #3 20050816 21:16:41
Re: 0x∞=1 ???That is dependant on the fact that n/0=∞, which I don't like. I prefer the idea that as 6x0=0, then 0/0=6, with 6 being replaced with any number. As 0/0 can take any value, then it is undefined. Why did the vector cross the road? It wanted to be normal. #4 20050817 17:26:52
Re: 0x∞=1 ???Too complex for the human brain to comprehend..... Character is who you are when no one is looking. #6 20050906 09:04:53
Re: 0x∞=1 ???
With "∞ = 1/0" reasoning, we could argue that 2/0 is also ∞, and so on. From this, 0 x ∞ could be any number. Letting n/0 = ∞ is just illegal to me. True, n/m gets increasingly closer to ∞ as m gets closer to 0(from the right), but when m actually is 0, we don't have any sensible number to assign to it. Assigning ∞ to n/0 doesn't make any sense unless n = 0, making it so 0 x ∞ = 0, but then we run into the classic indeterminate form 0/0, which can be any number. As mathsyperson said, dealing with 0 like this brings us into an area of mathematics which we cannot explain. #7 20050906 09:55:46
Re: 0x∞=1 ???But the slope of vertical line can also be negative infinity too! Last edited by John E. Franklin (20050906 09:56:36) igloo myrtilles fourmis #8 20051031 12:17:36
Re: 0x∞=1 ???General comments: Last edited by God (20051031 12:18:02) #9 20051031 16:18:30
Re: 0x∞=1 ???Well, if God says it isn't a number, who are we to argue? "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman 