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Hi! can you teach me how to do this thing?I'm really confused... so please~~ THANK YOU~Solve:ln (x^2 + 1) = 2 ln (x + 1)andlog (7x - 12) = 2 log x
Use the identity a log b = log (b^a).1) ln (x²+1) = 2 ln (x+1)ln (x²+1) = ln (x+1)²x²+1 = x²+2x+12x = 0x = 02) log (7x-12) = 2 log xlog (7x-12) = log (x²)7x-12 = x²x²-7x+12 = 0(x-4)(x-3) = 0x = 3 or 4
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