Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

Pages: **1**

**tony123****Member**- Registered: 2007-08-03
- Posts: 189

jane and olivia both celebrate their birthday today. In three years, jane

will be four times as old as olivia was when jane was two years older than

olivia is today. If olivia is a teenager, how old is jane now?

Offline

**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

Offline

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 91,543

This is a nice problem that I found while looking through the oldies here. I know this has already been answered by Jane which seems apt. I still enjoyed working on it.

We call the variables:

Agediff - the difference between Jane's and Olivia's ages.

Jage Jane's age now, what we want.

Oage Olivia's age now.

Jthen Jane's age then ( 2 years older than olivia is now )

Othen Olivia'a age when Jane was 2 years older.

We get the following equations.

Eliminating Jthen:

Eliminating Agediff:

Eliminating Othen:

Easy to solve:

Jage = Jane's age = 25

Oage = Olivia's age = 15

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

**Online**

**gurthbruins****Member**- Registered: 2010-05-09
- Posts: 157

A fun problem. My solution:

*It's the activity of the intelligence above all that gives charm to existence.*

Offline

Pages: **1**