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Exclusive of the numbers 1 and 1176, how many factors are there for the number 1176. a.20b. 22c.24d. 26is there any trick to solve?
In general...If a number N has prime factorization as follows...N=ap×bq×cr...Then the number of distinct factors, including 1 and N is given by...Number of Factors = (p+1)(q+1)(r+1)...Here, 1176 = 23×31×72∴ Number of factors = (3+1)(1+1)(2+1) = 24
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