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#1 2005-09-21 12:19:11
- notamathperson
- Novice
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Imaginary Numbers
I understand my homework pretty well this time, but I do have a couple questions:
Simplify (√-4) x (√-8)
I ended up getting 2√8, but I'm not sure if this is correct
Also, can this number be simplified any more: (2+2i√14) / 6?
Specifically, can the square root be simplified or could it look something like this: (1+i√14) / 3?
#2 2005-09-21 13:28:28
- kylekatarn
- Power Member
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Re: Imaginary Numbers
√(-4).√(-8) = √(4)i.√(8).i = 2√(8).i² = -2√(8) = -2√(2³) = -2√(2.2²) = -4√(2)
Code:
2 + 2i√14 2 2i√14 1 √14 1+i√14
--------- = - + ----- = - + ---i or, if you want ------
6 6 6 3 3 3#4 2005-09-21 18:18:23
- MathsIsFun
- Administrator
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Re: Imaginary Numbers
Ohhh, multiplying negative square roots is a weird one.
Perhaps it should be: ±4√(2)
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman